1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
inna [77]
3 years ago
10

From 1st principle find the derivative of log (ax+b)

Mathematics
1 answer:
OLga [1]3 years ago
5 0

Answer:

Step-by-step explanation:

The parent function here is y = log x, where 10 is the base.

The derivative of y = log x is dy/dx = (ln x) / ln 10.

The derivative of y = log (ax+b) is found in that manner, but additional steps are necessary:  differentiate the argument ax + b:

The derivative with respect to 10 of log (ax + b) is:

dy/dx = [ 1 / (ax + b) ] / [ ln 10 ] *a, where a is the derivative of (ax + b).

Alternatively, we could express the answer as

dy/dx = [ a / (ax + b) ] / [ ln 10 ]

You might be interested in
How do I solve this problem, or can I have an answer to this problem?
azamat
Well first you have to know what i is. i is the sqrt of -1 so try doing 3+5(sqrt-1)/1+sqrt-1. I don't know how to solve it though sorry
7 0
3 years ago
The fastest speed at table tennis ball has been hit is 21.12 faster than the speed for the fastest swimmer. What is the speed fo
Juli2301 [7.4K]

Remark

You cannot give an answer to this unless you are give the fastest speed of a swimmer. That stat is not an easy one to decide upon. At what distance for example or do you eliminate distance? Since this is a college level question, I don't think it unreasonable that you have to research raw distance over fastest time.

The fastest speed I can find is 100 meters in 46.91 seconds.  That means that the actual speed of the swimmer is 100 meters / 46.91 = 2.132 meters / second.

Givens

Set up a proportion with the numbers found and given

Speed of ball / speed of swimmer = 21.12 / 1

Speed of ball = x

Solution

Speed of swimmer = 2.132 m/s

x / 2.132 = 21.12 / 1          Multiply Both sides by 2.132

x = 21.12 * 2.132 / 1

x = 45.02 m/s

Answer

45.02 m/s

8 0
3 years ago
Read 2 more answers
A square dancing contest has 256 teams of 3 pairs each. How many dancers are participating in the contest?
stiv31 [10]

Answer:

that will be 768!!!

Step-by-step explanation:

4 0
3 years ago
I need help with this question
Sonbull [250]

= 4 (6) - 4 (√2) + √2 (6) - √2 <span>√2
</span>= 24 - 4√2  + 6√2 - 2 
= (24 - 2)  +  (- 4√2  + 6√2)
= 22 + √2(- 4 + 6)
= 22 + √2 (2)
= 22 + 2√2

hope it helps
5 0
3 years ago
Determine the x and y intercepts
kakasveta [241]
Answer:
x-intercepts: (2,0), (4,0)
y-intercepts: (0,-8)

Explanation:
To find the x intercept(s), you must compute where y=0. So solve 0= -x^2 + 6x - 8. So, the x intercepts are: (2,0) and (4,0) since the solutions to the mentioned equation are x=2 and x=4. To find the y intercept(s) compute what is y when x=0. In this case, when x=0, y=-8. So the only y intercept is (0,-8).
5 0
2 years ago
Other questions:
  • Circle circumference using c=2pie 8m
    9·1 answer
  • Factor a number, variable, or expression out of the polynomial shown below. 15x^3 + 20x
    5·1 answer
  • A rectangular garden is 10 ft longer than it is wide. Its area is 1575 ft. What are its dimensions?
    14·1 answer
  • A square has a perimeter of 36 millimeters. What is the area of the square?
    11·2 answers
  • What is the general equation of a line?
    10·2 answers
  • How many flowers, spaced every 4 inches, are needed to surround a circular garden with a 200 inch radius?
    12·1 answer
  • A cell phone company offers two different monthly text-messaging plans as shown in the table below. For what number of text mess
    11·1 answer
  • What is the value of x
    8·2 answers
  • Combine like terms to create an equivalent expression.
    10·2 answers
  • Assume a fair, six sided die is rolled four times. What is the probability of rolling at least one six?
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!