I’d say A: congruent by SSS because the sides are labeled as equal and they share the other side.
Answer:
she will need to sell 3 cokes a day to sell all of them in 9 days
Step-by-step explanation:
20 divided by 9 =2.2
Answer:
The exact values of roots:
![$x_{1}=\frac{-3+\sqrt{33}}{6}$](https://tex.z-dn.net/?f=%24x_%7B1%7D%3D%5Cfrac%7B-3%2B%5Csqrt%7B33%7D%7D%7B6%7D%24)
![$x_{2}=\frac{-3-\sqrt{33}}{6}$](https://tex.z-dn.net/?f=%24x_%7B2%7D%3D%5Cfrac%7B-3-%5Csqrt%7B33%7D%7D%7B6%7D%24)
Approximation:
![x_{1}\approx0.457](https://tex.z-dn.net/?f=x_%7B1%7D%5Capprox0.457)
![x_{2}\approx -1.457](https://tex.z-dn.net/?f=x_%7B2%7D%5Capprox%20-1.457)
Step-by-step explanation:
![3x^2 + 3x =2\\3x^2 + 3x -2=0](https://tex.z-dn.net/?f=3x%5E2%20%2B%203x%20%3D2%5C%5C3x%5E2%20%2B%203x%20-2%3D0)
Using the quadratic formula:
![$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$](https://tex.z-dn.net/?f=%24x%3D%5Cfrac%7B-b%5Cpm%20%5Csqrt%7Bb%5E2-4ac%7D%7D%7B2a%7D%24)
![$x=\frac{-3\pm \sqrt{3^2-4\cdot \:3\left(-2\right)}}{2\cdot \:3}$](https://tex.z-dn.net/?f=%24x%3D%5Cfrac%7B-3%5Cpm%20%5Csqrt%7B3%5E2-4%5Ccdot%20%5C%3A3%5Cleft%28-2%5Cright%29%7D%7D%7B2%5Ccdot%20%5C%3A3%7D%24)
![$x=\frac{-3\pm\sqrt{33}}{2\cdot \:3}$](https://tex.z-dn.net/?f=%24x%3D%5Cfrac%7B-3%5Cpm%5Csqrt%7B33%7D%7D%7B2%5Ccdot%20%5C%3A3%7D%24)
![$x=\frac{-3\pm\sqrt{33}}6}$](https://tex.z-dn.net/?f=%24x%3D%5Cfrac%7B-3%5Cpm%5Csqrt%7B33%7D%7D6%7D%24)
Let's solve your inequality step-by-step.<span><span>12+<span>10w</span></span>≥<span>8<span>(<span>w+12</span>)
</span></span></span>Step 1: Simplify both sides of the inequality.<span><span><span>10w</span>+12</span>≥<span><span>8w</span>+96
</span></span>Step 2: Subtract 8w from both sides.<span><span><span><span>10w</span>+12</span>−<span>8w</span></span>≥<span><span><span>8w</span>+96</span>−<span>8w</span></span></span><span><span><span>2w</span>+12</span>≥96
</span>Step 3: Subtract 12 from both sides.<span><span><span><span>2w</span>+12</span>−12</span>≥<span>96−12</span></span><span><span>2w</span>≥84
</span>Step 4: Divide both sides by 2.<span><span><span>2w</span>2</span>≥<span>842</span></span><span>w≥42
</span>
Answer:<span>
w≥<span>
42
Good luck mate :P</span></span>
Let x mi/h be the speed of the boat in still water and y mi/h be the speed of stream.
1) Downstream.
The speed of the boat travelling downstream is x+y mi/h. Then
![(x+y)\cdot 10=280.](https://tex.z-dn.net/?f=%28x%2By%29%5Ccdot%2010%3D280.)
2) Upstream.
The speed of the boat travelling upstream is x-y mi/h. Then
![(x-y)\cdot 20=280.](https://tex.z-dn.net/?f=%28x-y%29%5Ccdot%2020%3D280.)
3) Solve the system of equations:
![\left\{\begin{array}{l}(x+y)\cdot 10=280\\ \\(x-y)\cdot 20=280\end{array}\right.\Rightarrow \left\{\begin{array}{l}x+y=28\\ \\x-y=14\end{array}\right..](https://tex.z-dn.net/?f=%5Cleft%5C%7B%5Cbegin%7Barray%7D%7Bl%7D%28x%2By%29%5Ccdot%2010%3D280%5C%5C%20%5C%5C%28x-y%29%5Ccdot%2020%3D280%5Cend%7Barray%7D%5Cright.%5CRightarrow%20%5Cleft%5C%7B%5Cbegin%7Barray%7D%7Bl%7Dx%2By%3D28%5C%5C%20%5C%5Cx-y%3D14%5Cend%7Barray%7D%5Cright..)
Add these two equations:
![x+y+x-y=28+14,\\ \\2x=42,\\ \\x=21\text{ mi/h}.](https://tex.z-dn.net/?f=x%2By%2Bx-y%3D28%2B14%2C%5C%5C%20%5C%5C2x%3D42%2C%5C%5C%20%5C%5Cx%3D21%5Ctext%7B%20mi%2Fh%7D.)
Subtract these two equations:
![x+y-x+y=28-14,\\ \\2y=14,\\ \\y=7\text{ mi/h}.](https://tex.z-dn.net/?f=x%2By-x%2By%3D28-14%2C%5C%5C%20%5C%5C2y%3D14%2C%5C%5C%20%5C%5Cy%3D7%5Ctext%7B%20mi%2Fh%7D.)
Answer: the speed of the boat in still water is 21 miles per hour and the speed of the stream is 7 miles per hour.