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Charra [1.4K]
3 years ago
15

Find the volume of a box that is 2 in x 4 in x 3 in.

Mathematics
2 answers:
Scrat [10]3 years ago
5 0

Answer:

D) 24 in3

Step-by-step explanation:

Volume of a box is length times width times height

2 in x 4 in x 3 in = 24

and its inches cubed because inches is multiplied 3 times

vovikov84 [41]3 years ago
4 0

Answer:

Step-by-step explanation: it’s C

2x4x3

8x3

24 2in

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PLEASE HELP!!!! WILL GIVE BRAINLEST
tiny-mole [99]

Answer:

31

Step-by-step explanation:

Since the two sides are equal, the two angles are equal

8x-1 = 5x+11

Subtract 5x from each side

8x-5x -1 = 5x-5x+11

3x-1 =11

Add 1 to each side

3x-1+1 =11+1

3x =12

Divide by 3

3x/3 =12/3

x =4

Now we can find WZY

5x+11

5(4)+11

20+11

31

4 0
3 years ago
Show that the equation x3 + 4x = 1 has a solution between x = 0 and x = 1
nexus9112 [7]

Intermediate Value Theorem: Suppose that  f(x)  is an arbitrary, continuous function on an interval  [a,b] . If there exists a value  L  between  f(a)  and  f(b) , then there exists a corresponding value  c∈(a,b) , such that  f(c)=L

f(x)=x3+4x−1

f(0)=−1f(1)=4

Since the function changes sign in the interval  (0,1) , hence there exists a  c∈(0,1)  such that  f(c)=0

5 0
2 years ago
Which triangle congruence is this?<br> SSS<br> SAS<br> ASA<br> AAS<br> HL
MrRissso [65]

Answer:

HL

Step-by-step explanation:

The Hypotenuse-Leg Theorem states that two right triangles are congruent if and only if the hypotenuse and a leg of one right triangle are congruent to the hypotenuse and a leg of the other right triangle.

7 0
3 years ago
The graph of an absolute value function opens up and has a vertex of (0, -3).
Ad libitum [116K]
Absolute value function domain is all real numbers

absolute value has vertex of(0,-3)
and it opens up
means that the lowest y value is -3
highest is infinity


domain=-inifnity to infinity
range=-3 to positive initnify

the answer is C for the domain and B for the range
4 0
2 years ago
Read 2 more answers
Please help ill give brainliest pls dont guess
LiRa [457]
When y=2 and y=5

1. 2y-1 and (3y-5+y or 4y-5)
when y=2 ; 2(2)-1 = 3 and 4(2)-5=3
when y=5 ; 2(5)-1 = 9 and 4(5)-5=15

----nonequivalent-----

2.5y+4 and (7y+4-2y or 5y+4)
so you don't have to place any value in because 5y+4 and 7y+4-2y are equal,
whatever you place any value in, it will be all the same then

-----equivalent------

and no need to find more
7 0
2 years ago
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