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Contact [7]
3 years ago
5

What is the value of n in the relationship 8n+9=-n+5

Mathematics
1 answer:
vitfil [10]3 years ago
8 0
Subtract 5 from both sides.

8n + 4 = -n

Subtract 8n from both sides.

4 = -9n

Divide both sides by -9 to solve for n.

- \frac{4}{9} = n

The value of n is -4/9.
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Two supplementary angles are in the ratio of 1 to 3. The measure of the larger angle is
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I did the math and I think it should be 67.5
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3 years ago
Calculate the area of triangle ABC with altitude CD, given A (6, -2), B (1, 3), C (5, 5), and D (2, 2).
Flura [38]

Answer:

15 units

Step-by-step explanation:

I just took this geometry test with the same question. Its 15

3 0
3 years ago
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Can you please help me with this! It's due in a couple hours.
castortr0y [4]

Answer:

f(2) = -5

Step-by-step explanation:

A point (x, y) lying on a function represents output value (y-value) of the function for any input value (x-value).

In other words y = f(x) for any input value of 'x'.  

From the graph attached,

For the input value x = 2,

Output value of the function is y = -5

Therefore, f(2) = -5 will be the answer.

5 0
3 years ago
I don't need an answer anymore.
Ghella [55]
Is this a question? Or what is the question if you first said it?
4 0
3 years ago
A solid oblique pyramid has an equilateral triangle as a base with an edge length of 4 cm and an area of 12 cm2. What is the vol
Pavel [41]

Solution:

Let me define pyramid first.A pyramid is a Polyhedron , whose base  can be any polygon and it's faces are triangular which meet at a point called vertex.

Volume of Pyramid =  \frac{1}{2}\times{\text{Area of Base}\times{\text{Height}

Side of base which is an equilateral triangle= 4 cm

Area of whole pyramid = 12 square cm

Area of Equilateral triangle having side 4 cm=\frac{\sqrt3}{4}\times(Side)^2=\frac{\sqrt3}{4}\times(4)^2=4 \sqrt3 cm²

So, Area of three triangle which are faces of pyramid = (12 - 4 √3)cm²

Area of triangle = \frac{1}{2} \times (Base)\times(Height)

12 - 4 √3= \frac{1}{2} \times (4)\times(Height)

Height =\frac{12-4\sqrt3}{2}

Height=(6-2√3) cm

Volume of pyramid = Area of Equilateral triangle which is it's Base × Height of Pyramid

          =4√3 × (6-2√3) cm³

           =(24 √3 -24)

           = 24 (1.732-1)

          =24 × 0.732

          =17.568 cm³



8 0
3 years ago
Read 2 more answers
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