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kati45 [8]
3 years ago
15

Let ModifyingBelow lim With x right arrow 6 f (x )equals 4 and ModifyingBelow lim With x right arrow 6 g (x )equals 6. Use the l

imit rules to find the following limit. ModifyingBelow lim With x right arrow 6 StartFraction f (x )plus g (x )Over 6 g (x )EndFraction
Mathematics
1 answer:
Charra [1.4K]3 years ago
8 0

Answer:

5/3

Step-by-step explanation:

\lim_{x \to 6} f(x) =4; and \lim_{x \to 6} g(x) =6\\ \lim_{x \to 6} \dfrac{f(x)+g(x)}{g(x)} =?

Using the laws of limits,

\\ \lim_{x \to 6} \dfrac{f(x)+g(x)}{g(x)} =  \dfrac{lim_{x \to 6}f(x)+lim_{x \to 6}g(x)}{lim_{x \to 6}g(x)}, lim_{x \to 6}g(x)\neq 0

Thus,

\dfrac{lim_{x \to 6}f(x)+lim_{x \to 6}g(x)}{lim_{x \to 6}g(x)} =\frac{4+6}{6} =\frac{10}{6}=\frac{5}{3}

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4 years ago
According to a survey, the average American person watches TV for 3 hours per week. To test if the amount of TV in New York City
Neporo4naja [7]

Answer:

Test statistic (t-value) of this one-mean hypothesis test is -2.422.

Step-by-step explanation:

We are given that according to a survey, the average American person watches TV for 3 hours per week. She surveys 19 New Yorkers randomly and asks them about their amount of TV each week, on average. From the data, the sample mean time is 2.5 hours per week, and the sample standard deviation (s) is 0.9 hours.

We have to test if the amount of TV in New York City is less than the national average.

Let Null Hypothesis, H_0 : \mu \leq 3  {means that the amount of TV in New York City is less than the national average}

Alternate Hypothesis, H_1 : \mu > 3   {means that the amount of TV in New York City is more than the national average}

The test statistics that will be used here is One-sample t-test statistics;

        T.S. = \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, \bar X = sample mean time = 2.5 hours per week

             s = sample standard deviation = 0.09 hours

             n = sample size = 19

So, <u>test statistics</u> = \frac{2.5 - 3}{\frac{0.9}{\sqrt{19} } } ~ t_1_8

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Therefore, the test statistic (t-value) of this one-mean hypothesis test (with σ unknown) is -2.422.

8 0
4 years ago
Is what I have correct answer right away 100 points!!!!!
Semmy [17]
That's correct, because I learned it in math already


7 0
3 years ago
Read 2 more answers
Find the sum of 0.333......and 0.444....​
SashulF [63]

Answer:

0.777......

Step-by-step explanation:

0.333...... + 0.444....​..

= 0.777......

Hope it helps :)

Please mark my answer as the brainliest

7 0
3 years ago
Read 2 more answers
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