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3 years ago

If (x+2) Is a factor of x^3-6x^2+kx+10 k=?

Mathematics

1 answer:

Arlecino [84]3 years ago

7 0

The value of k is -11

Further explanation:

Any number being a factor states that the value of expression will be equal to zero at the factor.

Given

$x^3-6x^2+kx+10$

and

x+2 is a factor

x+2 = 0

x=-2

If x=-2 is a factor of given expression then the expression will be zero at x=-2

So.

$(-2)^3-6(-2)^2+k(-2)+10 = 0\\-8-6(4)-2k+10 = 0\\-8-24-2k+10 = 0\\-22-2k=0\\-2k=22\\k = -11$

The value of k is -11

Keywords: Synthetic division, Factorization

Learn more about synthetic division at:

#LearnwithBrainly

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noname [10]

Answer:

f(x) = 9(5/3)^x

Step-by-step explanation:

f(x) = a(b^x)

x = 0

9 = a(b⁰)

9 = a

f(x) = 9(b^x)

x = 1

15 = 9(b¹l

b = 15/9

b = 5/3

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3 years ago

I an a factor of 28. the other factor is 4. what number am i

Kaylis [27]

Hello there!

The correct answer is 7

Because 7 * 4 = 28

I hope this helps!

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3 years ago

Read 2 more answers

What does 4 3/10 equal

Dmitriy789 [7]

Using your talking about putting it into an improper fraction. it would be 43/10.

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2 years ago

David’s bank offers a 36-month Certificate of Deposit (CD) with an APR of 2.25%. Use the compound interest formula to answer the

tamaranim1 [39]

Using compound interest, it is found that:

a) A(8) = 2389.66

b) t = 31.15

c) P = 1870.85

Compound interest:

$A(t) = P\left(1 + \frac{r}{n}\right)^{nt}$

A(t) is the amount of money after t years.
P is the principal(the initial sum of money).
r is the interest rate(as a decimal value).
n is the number of times that interest is compounded per year.
t is the time in years for which the money is invested or borrowed.

In this problem:

The APR is of 2.25%, hence $r = 0.0225$ .

No information about the number of compounding per year, hence $n = 1$ .

Item a:

$P = 2000$ , hence:

$A(t) = P\left(1 + \frac{r}{n}\right)^{nt}$

$A(8) = 2000\left(1 + \frac{0.0225}{1}\right)^{8}$

$A(8) = 2389.66$

Item b:

$A(t) = 4000$ , hence:

$A(t) = P\left(1 + \frac{r}{n}\right)^{nt}$

$4000 = 2000\left(1 + \frac{0.0225}{1}\right)^{t}$

$(1.0225)^t = 2$

$\log{(1.0225)^t} = \log{2}$

$t\log{1.0225} = \log{2}$

$t = \frac{\log{2}}{\log{1.0225}}$

$t = 31.15$

Item c:

$A(3) = 2000$ , hence:

$A(t) = P\left(1 + \frac{r}{n}\right)^{nt}$

$2000 = P\left(1 + \frac{0.0225}{1}\right)^{3}$

$P = \frac{2000}{(1.0225)^3}$

$P = 1870.85$

A similar problem is given at brainly.com/question/24850750

7 0

2 years ago

Which unit would you need fewer of to measure a tree?

NemiM [27]

Answer:

You would need fewer the unit kilometer (km) to measure a tree.

Explanation:

In the internet you can find that the greatest height of a tree is aobut 115 meters.

Thus, you would never expect to find a tree measuring kilometers or miles.

If you used kilometers as unit, the measure of the tallest tree woul be about 0.115 km (115 meter divided by 1,000).

Most of the trees meausre in the range of 1 to 20 meters. That would be 0.001 km to 0.020 km.

Thus, kilometer is not a unit that you would need to measure a tree. You'd rather use centimeters, when the tree is small, and meters for most of the trees. You may also use feet, since 1 meter is about 3.28 feet, or even yards, since 1 yard is equal to 3 feet.

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3 years ago