If (x+2) Is a factor of x^3-6x^2+kx+10 k=?

1 answer:

7 0

The value of k is -11

Further explanation:

Any number being a factor states that the value of expression will be equal to zero at the factor.

Given

$x^3-6x^2+kx+10$

and

x+2 is a factor

x+2 = 0

x=-2

If x=-2 is a factor of given expression then the expression will be zero at x=-2

So.

$(-2)^3-6(-2)^2+k(-2)+10 = 0\\-8-6(4)-2k+10 = 0\\-8-24-2k+10 = 0\\-22-2k=0\\-2k=22\\k = -11$

The value of k is -11

Keywords: Synthetic division, Factorization

Learn more about synthetic division at:

#LearnwithBrainly

You might be interested in

navik [9.2K]

Answer:

The square root of 244 is 15.62 ( up-to 2 decimal places)

Step-by-step explanation:

Following is the division method for square root of 244 with rules as follows:

Make pairs of the given digit starting from right (unit place). They will be calculated one by one as formed in pairs/singles.
Digit added for divisor and quotient will be same at each step.
Each next dividend will be formed by subtracting product of divisor and quotient from first digit/pair.
Each next divisor will be formed by taking two times of previous quotient and annexing it with suitable digit that gives equal to or less than the dividend.

Following solution gives square root of 244:

I hope it will help you!