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Pavlova-9 [17]
3 years ago
6

Edward solved the equation 4x + 1 = 5x + (−5) using these steps. 1. Add 4 negative x-tiles to both sides. 2. Add 5 negative unit

tiles to both sides. 3. Solution x = −4.
Mathematics
2 answers:
8_murik_8 [283]3 years ago
8 0

Answer:

The solution for the given expression x ix 6.

Step-by-step explanation:

4x + 1 = 5x + (-5)

Solution:

Step 1: Adding (-4x) on both sides

4x + 1 +(-4)= 5x + (-5)+(-4x)

1=-5+1x

Step 2: Adding (5) on both sides:

1+5=-5+1x+5

6=x

The solution for the given expression x ix 6.

Ivanshal [37]3 years ago
5 0
4x + 1 = 5x + (-5)
1 = x + (-5)
6 = x
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A parabola can be drawn given a focus of (0,−6) and a directrix of y=−2. Write the equation of the parabola in any form.
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Answer:

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Step-by-step explanation:

The vertex of a parabola is exactly halfway between the focus and the directrix.  If the focus is at (0, -6) and the directrix is the line y = -2, then we do this to locate the vertex:  Draw a vertical line through (0, -6) also crossing the line y = -2.  The y value halfway between y = -6 and y = -2 is y = -4, and the vertex is thus (0, -4).

Using the vertex method, write out the equation of this parabola, starting with the general form y - k = (x-h)^2, where (h, k) is the vertex.  Here h = 0 and k = -4

We get:  y + 4 = (x - 0)^2, or y + 4 = x^2, or y = x^2 - 4.  As a check, let x = 0; y = -4, which is the y-coordinate of the vertex.

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3 years ago
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Write the equation of the parabola in vertex form. <br> vertex (2,1) point (3,-3)
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first off let's notice that hmmm the vertex is above the point (3,-3), so if we "assume" is a vertical parabola, then it'd be opening downwards.... anyhow that said, let's plug in those values.

\bf ~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{"a"~is~negative}{op ens~\cap}\qquad \stackrel{"a"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf vertex~~(\stackrel{h}{2}~~,~~\stackrel{k}{1})\qquad \implies \qquad y = a(x-2)^2+1 \\\\\\ \stackrel{\textit{we also know that }}{(3~~,~~-3)} \begin{cases} x = 3\\ y = -3 \end{cases}\qquad \implies -3=a(3-2)^2+1 \\\\\\ -3=a(1)^2+1\implies -3=a+1\implies -4=a \\\\[-0.35em] ~\dotfill\\\\ ~\hfill y = -4(x-2)^2+1~\hfill

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3 years ago
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WARRIOR [948]

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Step-by-step explanation:

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