2(8 4/5)+2(22/25)
2(44/5)+2(22/25)
2(220/25)+2(22/25)
(440/25)+(44/25)
484/25=P
Answer:
2290 trees
Step-by-step explanation:
Given data
Let the total number of trees be x
62% of the total trees x is 1420 trees
mathematically
62/100x= 1420
0.62x= 1420
divide both sides by 0.62
x= 1420/0.62
x= 2290.32
To the nearest whole tree= 2290 trees
Let h represent the height of the trapezoid, the perpendicular distance between AB and DC. Then the area of the trapezoid is
Area = (1/2)(AB + DC)·h
We are given a relationship between AB and DC, so we can write
Area = (1/2)(AB + AB/4)·h = (5/8)AB·h
The given dimensions let us determine the area of ∆BCE to be
Area ∆BCE = (1/2)(5 cm)(12 cm) = 30 cm²
The total area of the trapezoid is also the sum of the areas ...
Area = Area ∆BCE + Area ∆ABE + Area ∆DCE
Since AE = 1/3(AD), the perpendicular distance from E to AB will be h/3. The areas of the two smaller triangles can be computed as
Area ∆ABE = (1/2)(AB)·h/3 = (1/6)AB·h
Area ∆DCE = (1/2)(DC)·(2/3)h = (1/2)(AB/4)·(2/3)h = (1/12)AB·h
Putting all of the above into the equation for the total area of the trapezoid, we have
Area = (5/8)AB·h = 30 cm² + (1/6)AB·h + (1/12)AB·h
(5/8 -1/6 -1/12)AB·h = 30 cm²
AB·h = (30 cm²)/(3/8) = 80 cm²
Then the area of the trapezoid is
Area = (5/8)AB·h = (5/8)·80 cm² = 50 cm²
Set up a ratio for this problem:
.25 in/50 miles = 2.5 in/x
.25x = 125
then divide by .25
The actual distance is: 500 miles
