I think it is repeatable, testable, observable
Answer:
PpDD and PpDd
Explanation:
Pigmented eyes (P) are dominant to non-pigmented (p), and dimpled chins (D) are dominant to Non-dimpled chins (d).
The <u>possible genotypes of a pigment-eyed, dimple-chinned person</u> would be PPDD, PpDd, PPDd, PpDD while a blue-eyed person without a dimpled chin would have the genotype ppdd.
The genotype of a blue-eyed, dimpled chin child would be either of ppDd or ppDD, but in this case, the mother is ppdd and as such, the child cannot have two copies of D allele. Hence, the genotype of the child can only be ppDd.
In order for the child to have blue eyes (pp), it means that the father has to have the non-pigmented allele (p). This also means that the father is heterozygous for eye pigmentation (Pp).
<em>Hence, the genotype of the father is now limited to </em><em>PpDD</em> <em>and </em><em>PpDd</em>.
The answer is C. This is because nucleotide elongation involves the addition of a nucleotide to the 3 prime carbon of the previous nucleotide carbon ring. This involves a dehydration reaction between the phosphate group on the 5 prime carbon of the last nucleotide to the hydroxyl group of the 3 prime carbon of the previous nucleotide.
Answer:
c.Racquetball
because the lighter the object the more force it needs to go
