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3 years ago

Q.2. Separate the digits of the number "893451" as per National and

Mathematics

1 answer:

LuckyWell [14K]3 years ago

8 0

Answer:

imm a bit sorry I could only answer the international one as the national is equal to international place value system

Step-by-step explanation:

eight hundred ninety three thousand four hundred fifty one

hth tth th h t o

8 9 3 4 5 1

I hope you understand

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2. Sam has two part-time jobs, delivering pizza and mowing lawns. He makes $9/hr delivering pizza and $7/hr mowing lawns. Last w

frutty [35]

Answer:

<h2>22 hours and 10 hours </h2>

Step-by-step explanation:

let the jobs be x and y, so that

x+y=32--------1

9x+7y=248----2

x=32-y

substitute x=32-y for x in equation 2 we have

9(32-y)+7y=248

open bracket we have

288-9y+7y=248

-2y=248-288

-2y=-40

2y=40

divide both sides by 2 we have

y=40/2

y= 10 hours

subtitute y=10 for y in equation 1 to find x

x+10=32--------1

x=32-10

x=22

x=22 hours

4 0

3 years ago

HELP ME PLEASEEEEEEE

igomit [66]

Answer:a

Step-by-step explanation:The temperature rose by 80 so up the number line and dropped 20 so down the number line to 60

4 0

3 years ago

Read 2 more answers

Match each series with the equivalent series written in sigma notation

PIT_PIT [208]

Answer:

$3 + 12 + 48 + 192 + 768 = \sum\limits^4_{n=0} 3 * 4^n$

$4 + 32 + 256 + 2048 + 16384 = \sum\limits^4_{n=0} 4 * 8^n$

$2 + 6 + 18 + 54 + 162 = \sum\limits^4_{n=0} 2* 3^n$

$3 + 15 + 75 + 375 + 1875 = \sum\limits^4_{n=0} 3* 5^n$

Step-by-step explanation:

Given

See attachment for complete question

Required

Match equivalent expressions

Solving (a):

$3 + 12 + 48 + 192 + 768$

The expression can be written as:

$3 \to 3*4^{0$ --- 0

$12 \to 3 * 4^{1$ ---- 1

$48 \to 3 * 4^{2$ --- 2

$192 \to 3 * 4^{3$ ---- 3

$768 \to 3 * 4^{4$ ---- 4

For the nth term, the expression is:

$Term = 3 * 4^{n$ ---- n

So, the summation is:

$3 + 12 + 48 + 192 + 768 = \sum\limits^4_{n=0} 3 * 4^n$

Solving (b):

$4 + 32 + 256 + 2048 + 16384$

The expression can be written as:

$4 \to 4 * 8^0$ --- 0

$32 \to 4 * 8^1$ ---- 1

$256 \to 4 * 8^2$ --- 2

$2048 \to 4 * 8^3$ ---- 3

$16384 \to 4 * 8^4$ ---- 4

For the nth term, the expression is:

$Term \to 4 * 8^n$ ---- n

So, the summation is:

$4 + 32 + 256 + 2048 + 16384 = \sum\limits^4_{n=0} 4 * 8^n$

Solving (c):

$2 + 6 + 18 + 54 + 162$

The expression can be written as:

$2 \to 2 * 3^0$ --- 0

$6 \to 2 * 3^1$ ---- 1

$18 \to 2 * 3^2$ --- 2

$54 \to 2 * 3^3$ ---- 3

$162 \to 2 * 3^4$ ---- 4

For the nth term, the expression is:

$Term \to 2 * 3^n$ ---- n

So, the summation is:

$2 + 6 + 18 + 54 + 162 = \sum\limits^4_{n=0} 2* 3^n$

Solving (d):

$3 + 15 + 75 + 375 + 1875$

The expression can be written as:

$3 \to 3 * 5^0$ --- 0

$15 \to 3 * 5^1$ ---- 1

$75 \to 3 * 5^2$ --- 2

$375 \to 3 * 5^3$ ---- 3

$1875 \to 3 * 5^4$ ---- 4

For the nth term, the expression is:

$Term \to 3 * 5^n$ ---- n

So, the summation is:

$3 + 15 + 75 + 375 + 1875 = \sum\limits^4_{n=0} 3* 5^n$

5 0

2 years ago

What is the sum of the prime factors of 2014

goblinko [34]

The sum of prime factors of 2014 is 74

<h3><u>Solution:</u></h3>

Given that to find sum of prime factors of 2014

Let us first find the prime factors of 2014

A prime number is a whole number greater than 1 whose only factors are 1 and itself

"Prime Factorization" is finding which prime numbers multiply together to make the original number.

<em><u>Prime factors of 2014:</u></em>

The Prime Factorization is:

$2014 = 2 \times 19 \times 53$

Thus the prime factors of 2014 are 2, 19, 53

<em><u>Let us now find the sum of prime factors of 2014</u></em>

sum of prime factors of 2014 = 2 + 19 + 53 = 74

Thus the sum of prime factors of 2014 is 74

7 0

2 years ago

PLEASE HELP! and also please show your work!!

FinnZ [79.3K]

Answer: d) b = 12

2/3.b - 1/3.b + 12 = 16

⇔ 1/3. b = 16 - 12

⇔ 1/3.b = 4

⇔ b = 4.3 = 12

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers