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Rus_ich [418]
3 years ago
11

A degenerate tree might actually be less efficient than a linked list. Why?

Computers and Technology
1 answer:
Alla [95]3 years ago
8 0

Answer:

A degenerate tree is a tree which has the pattern of the parent node attached only to single child node .It can work in a dynamic manner and are also considered similar as the linked list.

Linked list are the dynamically working data structures having elements of the list to be connected through pointers in a linear manner. The unbalanced nature of the degenerate tree makes it less efficient which results in the low performance .Thus, degenerate tree doesn't have efficiency similar to linked list.

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Question 2 (6 points)
Bumek [7]

Answer:

False

Explanation:

4 0
3 years ago
2. Which of the following is not one of the guidelines for using instant messaging?A.You can use in place of all face-to-face co
Alexxandr [17]

Answer:

A. You can use in place of all face-to-face communication.

Explanation:

Hope this helps

6 0
3 years ago
Remove gray from RGB Summary: Given integer values for red, green, and blue, subtract the gray from each value. Computers repres
sergejj [24]

Answer:  

Here is the C++ program:  

#include <iostream>   //to use input output functions    

using namespace std;   //to identify objects cin cout    

int main() {   //start of main method    

int red,green,blue,smallest;   //declare variables to store integer values of red,green, blue and to store the smallest value    

cout<<"Enter value for red: ";  //prompts user to enter value for red    

cin>>red;  //reads value for red from user    

cout<<"Enter value for green: ";  //prompts user to enter value for green  

cin>>green; //reads value for green from user    

cout<<"Enter value for blue: "; //prompts user to enter value for blue    

cin>>blue;   //reads value for blue from user    

//computes the smallest value  

if(red<green && red<blue) //if red value is less than green and blue values    

smallest=red;   //red is the smallest so assign value of red to smallest    

else if(green<blue)   //if green value is less than blue value    

smallest=green; //green is the smallest so assign value of green to smallest  

else //this means blue is the smallest    

smallest=blue;  //assign value of blue to smallest    

//removes gray part by subtracting smallest from rgb  

red=red-smallest; //subtract smallest from red    

green=green-smallest; //subtract smallest from green    

blue=blue-smallest; //subtract smallest from blue    

cout<<"red after removing gray part: "<<red<<endl;  //displays amount of red after removing gray    

cout<<"green after removing gray part: "<<green<<endl; //displays amount of green after removing gray  

cout<<"blue after removing gray part: "<<blue<<endl;  } //displays amount of blue after removing gray  

Explanation:  

I will explain the program using an example.    

Lets say user enter 130 as value for red, 50 for green and 130 for blue. So  

red = 130    

green = 50

blue = 130  

First if condition if(red<green && red<blue)   checks if value of red is less than green and blue. Since red=130 so this condition evaluate to false and the program moves to the else if part else if(green<blue) which checks if green is less than blue. This condition evaluates to true as green=50 and blue = 130 so green is less than blue. Hence the body of this else if executes which has the statement: smallest=green;  so the smallest it set to green value.    

smallest = 50    

Now the statement: red=red-smallest; becomes:    

red = 130 - 50    

red = 80    

the statement: green=green-smallest;  becomes:    

green = 50 - 50    

green = 0    

the statement: blue=blue-smallest; becomes:    

blue = 130 - 50    

blue = 80    

So the output of the entire program is:    

red after removing gray part: 80                                                                                                 green after removing gray part: 0                                                                                                blue after removing gray part: 80    

The screenshot of the program along with its output is attached.

5 0
3 years ago
In this lab, you create a programmer-defined class and then use it in a C++ program. The program should create two Rectangle obj
MakcuM [25]

The program based on the information given is illustrated below.

<h3>What is a program?</h3>

A computer program simply means a sequence of instructions in a programming language that is created for a computer to execute.

It should be noted that computer programs are among the component of software.

The program to create two rectangle objects and get their area and perimeter is depicted:

// Rectangle.cpp

using namespace std;

class Rectangle

{

public:

// Declare public methods here

void setLength(double);

void setWidth(double);

double getLength();

double getWidth();

double calculateArea();

double calculatePerimeter();

private:

// Create length and width here

double length, width;

};

void Rectangle::setLength(double len)

{

length = len;

}

void Rectangle::setWidth(double wid)

{

// write setWidth here

width = wid;

}

double Rectangle::getLength()

{

// write getLength here

return length;

}

double Rectangle::getWidth()

{

// write getWidth here

return width;

}

double Rectangle::calculateArea()

{

// write calculateArea here

return length*width;

}

double Rectangle::calculatePerimeter()

{

// write calculatePerimeter here

return 2*(length+width);

}

// This program uses the programmer-defined Rectangle class.

#include "Rectangle.cpp"

#include <iostream>

using namespace std;

int main()

{

Rectangle rectangle1;

Rectangle rectangle2;

rectangle1.setLength(10.0);

rectangle1.setWidth(5.0);

rectangle2.setLength(7.0);

rectangle2.setWidth(3.0);

cout << "Perimeter of rectangle1 is " << rectangle1.calculatePerimeter() << endl;

cout << "Area of rectangle1 is " << rectangle1.calculateArea() << endl;

cout << "Perimeter of rectangle2 is " << rectangle2.calculatePerimeter() << endl;

cout << "Area of rectangle2 is " << rectangle2.calculateArea() << endl;

return 0;

}

/*

output:

The perimeter of rectangle1 is 30

The area of rectangle1 is 50

The Perimeter of rectangle2 is 20

The area of rectangle2 is 21

*/

Learn more about program on:

brainly.com/question/1538272

#SPJ1

8 0
2 years ago
The order of precedence determine
Free_Kalibri [48]
The order of precedence is the hierarchical order in which calculations are conducted. The simplest example of this is the way you always multiply before you add numbers.
7 0
3 years ago
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