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lesya [120]
3 years ago
9

Find limit as x approaches 1 for x-1/ x^2-3x+2

Mathematics
1 answer:
zysi [14]3 years ago
8 0

I'm going to assume that you meant the following:

  (x-1)

---------------

x^2-3x+2


Factoring the denominator, we get:

  (x-1)

------------  

(x-1)(x-2)

Notice that we have x-1 in both the numerator and the denominator.  This factor cancels.  HOWEVER:  x can still not equal 1, which would lead to div. by zero.  With the factor x-1 cancelled, we have   1 / (x-2).  As x approaches 1 from either side, y approaches 1 / (1-2), or 1 / (-1), or -1.  Thus, the limit exists and is -1.

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