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3 years ago

List -4/5 1.1 -0.6 1/2 in least to greatest

Mathematics

1 answer:

inna [77]3 years ago

7 0

-0.6,1/2,4/5,1.1 !!!!!!!!!!!!!!!!!!!!!!!!!!!!!

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if Ms. sanchez has 32 students in her class, about how many students earned a grade of 80% or higher? about how many earned more

stealth61 [152]

Um, the picture is kind of blurry otherwise I can help since I am pretty good with this...

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2 years ago

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What is the difference between the formula of the volume of the cylinder and the volume of a cone? What do the formulas have in

Margaret [11]

Answer:

The volume of the cylinder is 3 times the volume of the cone

Step-by-step explanation:

The formula for the volume of the cylinder is given by :

$V_{cy}=\pi r^2 h$ .....(1)

Where

r and h are the radius and the height of the cylinder

The formula for the volume of the cone is given by :

$V_{cone}=\dfrac{1}{3}\pi r^2h$ ...(2)

From equation (1) and (2),

$\dfrac{V_{cy}}{V_{cone}}=\dfrac{\pi r^2 h}{\dfrac{1}{3}\pi r^2 h}\\\\=3\\\\V_{cy}=3\times V_{cone}$

So, the volume of the cylinder is 3 times the volume of the cone.

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2 years ago

What is (f+g) (x) f(x) = -3x g(x)=-2x^2+x as a polynomial or rational function in simplest form?

fredd [130]

Answer:

56xy23

Step-by-step explanation:

56 x 12 bhi 56 xy23

4 0

1 year ago

QUICKK

VLD [36.1K]

3x + 4(2) = 20
3x + 8 = 20
3x = 12
x = 4
(4,2)
You have y=2 then all you need to do is plug 2 into the y in the equation 3x + 4y = 20 and do the math to find x. Hope this helps

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2 years ago

Simplifying exponents (picture provided)

Hitman42 [59]

Answer:

<em>3^2 ; Option B</em>

Step-by-step explanation:

We are given the equation 3^ -6 * ( 3^4 / 3^0 )^2, which can be solved through the application of exponential rules;

$3^{ - 6 } * ( 3^{ 4 } / 3^{ 0 } )^{2} - take 3^{ 0 } as 1,\\\\3^{ - 6 } * ( 3^{ 4 } / 1 )^{2} - take 3^{4} to power of 2, ( * of exponents ),\\\\3^{ - 6 } * ( 3^{ 8 } ) - combine powers, adding exponents,\\\\3^{ - 6 + 8 } - add like terms,\\\\3^{2} \\\\Solution; 3^{2}$

<em>3^2 ; Option B</em>

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3 years ago

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