Answer:
no they are not because 11, 14 is the only one that has a vertices
Step-by-step explanation:
Answer:
the 3rd dot is correct........
A standard-form equation for the perpendicular line will have the x- and y-coefficients swapped and one of them negated. (This gives a line with a slope that is the negative reciprocal of the original line, as is required for a perpendicular line.) Thus, you can look for an equation of the form
2x +5y = c
for some constant c that make the line go through the required point. This is matched by the
2nd selection. It also tells you the coefficients of x and y will be in the ratio 2:5. The only other choice that has coefficients like this is the 3rd choice, but it has the sign wrong.
The only appropriate selectin is
2x + 5y = -10
Answer:

So then the best option on this case is:
A. 14 and 15
Step-by-step explanation:
When we have a right triangle we can use the Pythegorean identity given by:
(1)
Where Hip represent the hypothenuse. Opp represent the opposite side and Adj the adjacent side.
On this case we have given the hypothenuse assumed
because is the only possible reasonable value because
is a too much higher value
We have a ratio provided on this case, let's assume that the ratio is:


If we rpelace this condition into equation (1) we got:

And then we have this:


And then the opposite side is:

The perimeter is defined as the sum of all the sides, we can find the perimeter like this:

And replacing the values that we found we got:

So then the best option on this case is:
A. 14 and 15
I hope this helps you
13^2+12^2=19^2
169+144=361
313=361 false