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4 years ago

Evaluate (a + b)2 for a = 2 and b = 3. 10 25 13

Mathematics

2 answers:

vlada-n [284]4 years ago

6 0

Answer:

Step-by-step explanation:

(a+b)2

(2+3)2

5(2)

fgiga [73]4 years ago

5 0

Answer:

Step-by-step explanation:

( 2 + 3 ) × 2

5 × 2 = 10

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Bro please help I will Mark you as brainlist

scoundrel [369]

the first one is, yes by AA

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3 years ago

Which sentence is a example of the distributive property ? AND WHY!!!?

katrin [286]

Answer:

answer is C

Step-by-step explanation:

Because it gives clear distribution process.

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4 years ago

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Work the following pricing problems for services rendered. (For all calculations use hundredths.)

gayaneshka [121]

Labor time = 4 1/2 hours = 4.5 hours
overhead rate = 95% - mostly dependent on labor
retail price of parts = 134.75
total cost of job = 241.98

241.98 - 134.75 = 107.23
107.25 / (4.5 x 1.95) = 107.25 / 8.78 = 12.22 hourly rate

labor : 12.22 x 4.5 =   54.99
overhead: 54.99 x 95% =   52.24
retail price of parts   = <u>134.75</u>
total cost of job: 241.98

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3 years ago

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Determine whether angle ABC should be solved by using the Law of Sines or the Law of Cosines. Then solve the triangle.

drek231 [11]

Answer:

Law of Cosines

Angle A = 45°

Angle B = 51°

Angle C = 84°

Step-by-step explanation:

Law of sines is used when we are given

a) two angles and one side or

b) two sides and non-included angle

Law of cosines is used when we are given

a) three sides or

b) two sides and included angle

In the given question we are given three sides so, Law of Cosines will be used to solve the triangle.

Law of Cosines is:

$a^2 = b^2 + c^2 -2bccos A\\b^2 = a^2 + c^2 -2accos B\\c^2 = a^2 + b^2 -2abcosC$

We will find the three angles A ,B and C of the triangle using above formula.

a= 10, b=11, c=14

Putting values and finding angle A

$a^2 = b^2 + c^2 -2bccos A\\(10)^2 = (11)^2 + (14)^2 -2(11)(14)cosA\\100 = 121 + 196 -308cosA\\100 = 317 -308 cosA\\100-317 = -308cosA\\-217/-308 = cos A\\0.704 = cos A\\=> A = cos ^{-1}(0.704)\\A= 45$

Now finding angle B

$b^2 = a^2 + c^2 -2ac cos B\\(11)^2 = (10)^2 + (14)^2 - 2(10)(14)cosB\\121 = 100+196 - 280cosB\\121 -296 = -280cosB\\-175/-280 = cosB\\0.625 = cosB\\=> B = cos^{-1} (0.625)\\B = 51$

Now finding angle C

$c^2 = a^2 + b^2 -2abcosC\\(14)^2 =(10)^2 + (11)^2 -2(10)(11)cosC\\196 = 100+121 -220cosC\\196 -221 = -220cosC\\-25/-220 = cos C\\0.11 = cosC\\=> C = cos^{-1}(0.11)\\C= 84$

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3 years ago

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i have the same hundreds digits as ones. the value of my tens digit is 50. The value of my ones digit is four. the 3 digits are

Anna [14]

454

check...
same hundreds digit as ones : correct
value of tens digit is 50 : correct
value of ones digit is 4 : correct

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3 years ago