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Nataliya [291]
3 years ago
5

I searched for this and no one asked it so i

Mathematics
1 answer:
Gwar [14]3 years ago
4 0

Answer:

Big oof

Step-by-step explanation:

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Pls help me<br> 4(3-x)=6(x+2)+20
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x = -2

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2 years ago
Jameson collects eggs from his chickens every day. The graph shows the approximate number of eggs Jameson collects over a couple
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B

Step-by-step explanation:

Khan

help a sistah, follow their instah: emventures666

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8 0
4 years ago
A=(-2,-7) B=(-6,4) C=(-2,7) D=(2,4) What is the perimeter?
Nata [24]

 

\displaystyle\bf\\AB=\sqrt{\Big(-6-(-2)\Big)^2+\Big(4-(-7)\Big)^2}\\\\AB=\sqrt{\Big(-6+2\Big)^2+\Big(4+7\Big)^2}\\\\AB=\sqrt{\Big(-4\Big)^2+\Big(11\Big)^2}\\\\AB=\sqrt{16+121}\\\\\boxed{\bf AB=\sqrt{137}}

.

\displaystyle\bf\\BC=\sqrt{\Big(-2-(-6)\Big)^2+\Big(7-4\Big)^2}\\\\BC=\sqrt{\Big(-2+6\Big)^2+\Big(7-4\Big)^2}\\\\BC=\sqrt{\Big(4\Big)^2+\Big(3\Big)^2}\\\\BC=\sqrt{16+9}\\\\BC=\sqrt{25}\\\\\boxed{\bf BC=5}

.

\displaystyle\bf\\CD=\sqrt{\Big(2-(-2)\Big)^2+\Big(4-7\Big)^2}\\\\CD=\sqrt{\Big(2+2\Big)^2+\Big(4-7\Big)^2}\\\\CD=\sqrt{\Big(4\Big)^2+\Big(-3\Big)^2}\\\\CD=\sqrt{16+9}\\\\CD=\sqrt{25}\\\\\boxed{\bf CD=5}

.

\displaystyle\bf\\AD=\sqrt{\Big(2-(-2)\Big)^2+\Big(4-(-7)\Big)^2}\\\\AD=\sqrt{\Big(2+2\Big)^2+\Big(4+7\Big)^2}\\\\AD=\sqrt{\Big(4\Big)^2+\Big(11\Big)^2}\\\\AD=\sqrt{16+121}\\\\\boxed{\bf AD=\sqrt{137}}

.

\displaystyle\bf\\P=AB+BC+CD+AD=\sqrt{137}+5+5+\sqrt{137}\\\\\boxed{\bf P=10+2\sqrt{137}}

 

4 0
3 years ago
Harvard University accepts 6 students for every 100 applicants how many students will be accepted if 850 applicants apply for ad
Iteru [2.4K]

Answer: 51 students


Step-by-step explanation: 850 divided by 100= Ans

Ans times 6= 51


*Hope this helps



8 0
3 years ago
Read 2 more answers
The diameter of a circle has endpoints (2,-6) and (-4,-16).
olga nikolaevna [1]

Answer:

(x + 1)^{2}  + (y + 11)^{2} = 34

Step-by-step explanation:

First find the midpoint of the segment  from (2, -6) to (-4, -16)

((2 - 4)/2, (-6 - 16)/2)

(-2/2, -22/2)

(-1, -11) is the midpoint and is the center of the circle

Now find the distance between the 2 given points and divide by 2 to get the radius of the circle

d = \sqrt{(2 + 4)^{2} + (-6 + 16)^{2}  }

  = \sqrt{6^{2} + 10^{2}  }

  = \sqrt{36 + 100}

  = \sqrt{136}

r = \sqrt{136}/2

r^{2} = 136/4 = 34

Equation of circle with center at (-1, -11) and radius = \sqrt{34} is

(x + 1)^{2}  + (y + 11)^{2} = 34

3 0
3 years ago
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