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2 years ago

Chords and arcs.find x

Mathematics

1 answer:

bagirrra123 [75]2 years ago

5 0

The chords SR and ST are congruent, so the (minor) arcs SR and ST have the same measure.

The measure of the arcs SR, ST, and RT add up to 360º. So we have

2<em>x</em>º + 64º = 360º ==> <em>x</em> = 148

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And replacing we got:

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And that represent $0.127 \frac{cm}{min}$

Step-by-step explanation:

For a tank similar to a cylinder the volume is given by:

$V = \pi r^2 h$

For this case we know that $r=5m$ represent the radius, $h = 10m$ the height and the rate given is:

$\frac{dV}{dt}= \frac{100 L}{min}$

For this case we want to find the rate of change of the water level when h =6m so then we can derivate the formula for the volume and we got:

$\frac{dV}{dt}= \pi r^2 \frac{dh}{dt}$

And solving for $\frac{dh}{dt}$ we got:

$\frac{dh}{dt}= \frac{\frac{dV}{dt}}{\pi r^2}$

We need to convert the rate given into m^3/min and we got:

$Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}$

And replacing we got:

$\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}$

And that represent $0.127 \frac{cm}{min}$

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3 years ago

Chords and arcs.find x​

Chords and arcs.find x