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nadya68 [22]
3 years ago
5

A bag contains 42 cups of dog food, your dog eats 2 and 1/3 cups a day, how many days does the dog food last?

Mathematics
1 answer:
Marina86 [1]3 years ago
8 0
You keep adding 2 and 1/3 to get your answer

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8090 [49]
Do 45/225 and simplify and that’s your answer
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I need help siwjjwnwnjsb ejwjennejejejene
makvit [3.9K]
The answer is 3 hope this helps
3 0
3 years ago
Can someone help me in #66
VladimirAG [237]
\bf log_{{  a}}(xy)\implies log_{{  a}}(x)+log_{{  a}}(y)
\\ \quad \\
% Logarithm of rationals
log_{{  a}}\left(  \frac{x}{y}\right)\implies log_{{  a}}(x)-log_{{  a}}(y)
\\ \quad \\
% Logarithm of exponentials
log_{{  a}}\left( x^{{  b}} \right)\implies {{  b}}\cdot  log_{{  a}}(x)\\\\
-------------------------------\\\\


\bf log_4\left( \cfrac{\sqrt{x^5y^7}}{zw^4} \right)\implies log_4(\sqrt{x^5y^7})-log_4(zw^4)
\\\\\\
log_4\left[(x^5y^7)^{^\frac{1}{2}}\right]-log_4(zw^4)\implies 
\cfrac{1}{2}log_4\left[(x^5y^7)\right]-log_4(zw^4)
\\\\\\
\cfrac{1}{2}\left[ log_4(x^5)+log_4(y^7) \right] -[log_4(z)+log_4(w^4)]
\\\\\\
\cfrac{1}{2}log_4(x^5)+\cfrac{1}{2}log_4(y^7)-[log_4(z)+log_4(w^4)]

\bf \cfrac{1}{2}\cdot 5log_4(x)+\cfrac{1}{2}\cdot 7log_4(y)-log_4(z)-4log_4(w)
\\\\\\
\cfrac{5}{2}log_4(x)+\cfrac{7}{2}log_4(y)-log_4(z)-4log_4(w)
6 0
3 years ago
Please help me thank you
Andreas93 [3]

Answer:

<em><u>1.c</u></em>

<em><u>2.b</u></em>

<em><u>3.a</u></em>

<em><u>4.d</u></em>

<em><u>5.c</u></em>

Step-by-step explanation:

<em><u>please click the heart and rate excellent and brainleist to </u></em><em><u>☻</u></em><em><u>❤</u></em><em><u>☺️</u></em><em><u>☺️</u></em><em><u>❤</u></em><em><u>☻</u></em>

5 0
3 years ago
Please help me !!!!!! I need help
kvv77 [185]

Answer:

  y +8 = -4(x -8)

Step-by-step explanation:

You recognize that the given equation is in slope-intercept form:

  y = mx + b

with m = 1/4 and b = 5.

A perpendicular line will have a slope that is the negative reciprocal of this value of m, so the desired slope is ...

  -1/m = -1/(1/4) = -4

The point-slope form of the equation for a line is ...

  y -k = m(x -h) . . . . . for slope m through point (h, k)

Using m=-4 and (h, k) = (8, -8), the point-slope form of the equation for the line you want is ...

  y +8 = -4(x -8)

3 0
3 years ago
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