7 is the square root of 49 and 8 is the square toot of 64.
randomly putting stuff i know in
Answer:
<h3>8</h3>
Step-by-step explanation:
If a coordinate point (x, y) is dilated by a factor k, then the resulting coordinate will be (kx, ky)
Given the coordinate (4,1), if this coordinate is dilated by a factor of 2 then the new coordinate points will be at (2(4), 2(1))
New point = (8, 2)
Hence x-coordinate of one of the the end point of the dilated segment is 8
<u>Answer</u>
√7 × √5
√3 × √2
<u>Explanation</u>
√9*√16 = 3 × 4
= 12
= 12/1 ⇒ It is a rational answer.
√7*√5 = √(7×5)
= √35
= 5.916079783.... ⇒ Irrational
√3*√2 = √(3×2)
= √6
= 2.449489743... ⇒ Irrational
4√2*√2 = 4 × √(2×2)
= 4 × √4
= 4 × 2
= 8
= 8/1 ⇒ It is rational
The expressions that would give irrational answers are: √7*√5 and√3*√2
Let's represent the two numbers by x and y. Then xy=60. The smaller number here is x=y-7.
Then (y-7)y=60, or y^2 - 7y - 60 = 0. Use the quadratic formula to (1) determine whether y has real values and (2) to determine those values if they are real:
discriminant = b^2 - 4ac; here the discriminant is (-7)^2 - 4(1)(-60) = 191. Because the discriminant is positive, this equation has two real, unequal roots, which are
-(-7) + sqrt(191)
y = -------------------------
-2(1)
and
-(-7) - sqrt(191)
y = ------------------------- = 3.41 (approximately)
-2(1)
Unfortunately, this doesn't make sense, since the LCM of two numbers is generally an integer.
Try thinking this way: If the LCM is 60, then xy = 60. What would happen if x=5 and y=12? Is xy = 60? Yes. Is 5 seven less than 12? Yes.
