Question

10) A worker performs a repetitive assembly task at a workbench to assemble products. Each product consists of 25 components. Various hand tools are used in the task. The standard time for the work cycle is 7.45 min, based on using a PFD allowance factor of 15%. If the worker completes 75 product units during an 8-hour shift, determine (a) the number of standard hours accomplished and (b) worker efficiency. (c) If the worker took only one rest break, lasting 13 min, and experienced no other interruptions during the 8 hours of shift time, determine her worker performance.

Answer 1

Answer:

a.9.313hr

b.116.4%

c.104.0%

Explanation:

(a) Hstd= 75(7.45)/60 = 558.75/60 = 9.313 hr

(b) Ew= 9.313/8.0 = 1.164 = 116.4%

(c) Time worked = 480 – 13 = 467 min

Tc= (467 min)/(75 pc) = 6.227 min/pc

Tn= 7.45/(1 + 0.15) = 6.478 min/pc

Pw= 6.478/6.227 = 1.040 = 104.0%