Your test scores for the semester are 87,84 and 85.Can you raise your test average to 90 with you next test?
1 answer:
You might be interested in
Answer:
Step-by-step explanation:
In order to solve all of these problems, you have to first create an equation. The typical format for an equation looks like this: y = mx + b
m is the slope and b is the y-intercept.
In order to create an equation, you have to find the slope and y-intercept of the function. You can find the slope using this expression: To find the y-intercept, you use a known point and the slope in the equation to solve for b.
Now that we know this, we can solve the problems.
1a.
To create the equation, let's find the slope using points (1, 15) and (2, 30)
= 15/1 = 15
The equation now looks like this: h = 15w + b
Let's use the point (1, 15) from the table to find b
15 = 15(1) + b
15 = 15 + b
subtract 15 from both sides the isolate the b
0 = b
There is no y-intercept for this equation, so the equation looks like this:
h = 15w
1b. We know the equation is h = 15w, so all we have to do is input the 9 into the equation.
h = 15(9)
h = 135
2a. We'll use the points (1, 8) and (2, 16) to find the slope
= 8/1 = 8
The slope is 8.
Since it's impossible to sell any houses in 0 months, we already know that there is no y-intercept, so the equation looks like this:
h = 8m
2b. Put the value of 15 inside the equation and solve.
h = 8(15)
h = 120
3a. We'll use the points (1, 35) and (2, 70) to find the slope.
= 35/1 = 35
The slope is 35.
It's impossible to see any movies in 0 months, so there is no y-intercept. The equation looks like this:
c = 35m
3b. We know that there are 12 months in a year, so put 12 into the equation and solve.
c = 35(12)
c = 420
4a. We'll use the points (1, 8) and (2, 16) to find the slope
= 8/1 = 8
The slope is 8.
It's impossible for there to be a cost if there are no hats, so the y-intercept must be 0. The equation looks like this:
c = 8h
4b. Put the 30 hats into the equation and solve.
c = 8(30)
c = 240
Step-by-step explanation:
Angles in the same segment. The angles at the circumference subtended by the same arc are equal. More simply, angles in the same segment are equal.
Picture 1 a° = a° they are the same
Picture 2 p= 52° q= 40° Angles in the same segment are equal. if they ask you to calculate you just show both angles p= 52 and q=40.
Picture 3 + 4 Let the obtuse angle MOQ = 2x.
Using the circle theorem, the angle at the centre is twice the angle at the circumference.
Therefore picture 4 tells us and proves;
Angle MNQ = x and angle MPQ = x.
Picture 5
A cyclic quadrilateral is a quadrilateral drawn inside a circle. Every corner of the quadrilateral must touch the circumference of the circle.
The second shape is not a cyclic quadrilateral. One corner does not touch the circumference.
Picture 6
The opposite angles in a cyclic quadrilateral add up to 180°.
a + c = 180°
b + d = 180°
Picture 7
Example
Calculate the angles a and b.
The opposite angles in a cyclic quadrilateral add up to 180°.
This is a picture that couldn't be added but has a quadrilateral occupying half the triangle consisting of 3 arcs the middle one was 140 and proved part of one triangle. The x (a) missing angle showed below a = 180-60 = 120 °
So hopefully this will help you remember the format here for quadrilateral shapes within a circle.
b = 180 - 140 = 40°
a = 180 - 60 = 120°
