All categories

2 years ago

HEEELLPPPPPPPPP PLEAS

Mathematics

2 answers:

krek1111 [17]2 years ago

6 0

E is 2/7 if not sorry

Temka [501]2 years ago

3 0

1. -5.6
2.-10.701
3. -46.644
4. -15/14
5. 2/7

You might be interested in

3. What is the area of the triangle below? Round your

Jobisdone [24]

Answer is A because when you work it out the area is 110.500 and rounding it makes it -

8 0

2 years ago

What is the value of x?

romanna [79]

Answer:

x=30

Step-by-step explanation:

7 0

2 years ago

2x^2+5x+3/x^2-3x-4 divided by 4x^2+2x-6/x^2-8x+16

Masja [62]

Answer: $\frac{x-4}{2x-2}$

Step-by-step explanation:

$\frac{2x^2+5x+3}{x^2-3x-4}$ divided by $\frac{4x^2+2x-6}{x^2-8x+16}$ is the same thing as multiplying $\frac{2x^2+5x+3}{x^2-3x-4}$ by $\frac{x^2-8x+16}{4x^2+2x-6}$ .

The equation we get is:

$\frac{2x^2+5x+3}{x^2-3x-4}*\frac{x^2-8x+16}{4x^2+2x-6}$

With this equation, we can factor each equation:

$\frac{(x+1)(2x+3)}{(x+1)(x-4)} *\frac{(x-4)(x-4)}{2(x-1)(2x+3)}$

We can cancel out like terms since they would be dividing each other:

$\frac{x-4}{2x-2}$

8 0

2 years ago

LAST ATTEMPT! MARKING AS BRAINLIEST!! ( simplifying radicals)

klasskru [66]

$\huge \bf༆ Answer ༄$

Let's solve ~

$\qquad \looparrowright \sf - 2 \sqrt{192 {k}^{4} }$

$\qquad \looparrowright \sf - 2 \sqrt{2 {}^{6} \times 3{k}^{4} }$

$\qquad \looparrowright \sf - 2 \times 2 {}^{3} \times {k}^{2} \times \sqrt{3}$

$\qquad \looparrowright \sf - 16 {k}^{2} \sqrt{3}$

Hence, the correct choice is D

5 0

2 years ago

Read 2 more answers

What is the solution to the equation 3/4y+1/4=1+y , given the replacement set {−4, −3, −2} ?

ivann1987 [24]

Answer:

It's -3 mate

Step-by-step explanation:

I just did the test

8 0

2 years ago