Question

Please!!! Help!!

Answer 1

well the intercepts are  (8,0) and (-4,0) its a lot of math so you need to find it i would show you but i have a quiz

im not sure tho soo

Answer 2

Answer:

The x-intercepts of the quadratic function are 8 and -4.

Step-by-step explanation:

The given function is

$f(x)=x^2-4x-32$

Equate the function f(x) equal to 0, to find the x-intercepts of the quadratic function.

$f(x)=0$

$x^2-4x-32=0$

The middle term can be written as -8x+4x.

$x^2-8x+4x-32=0$

$x(x-8)+4(x-8)=0$

Take out the common factors.

$(x-8)(x+4)=0$

Using zero product property,

$x-8=0\Rightarrow x=8$

$x+4=0\Rightarrow x=-4$

Therefore the x-intercepts of the quadratic function are 8 and -4.