Answer:
one solution
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
The information on the graph is almost symmetrical, because the lines look almost the same length on both sides.
Here, 2 1/4 r = 10
9/4 r = 10
r = 10*4 /9
r = 40 / 9
r = 4 4/9
In short, Your Answer would be Option C
Hope this helps!
Answer:

Step-by-step explanation:
Assuming a mean of $204 per night and a deviation of $55.
a. What is the probability that a hotel room costs $225 or more per night (to 4 decimals)?
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean"
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
Let X the random variable that represent the cost per night at the hotel, and for this case we know the distribution for X is given by:
Where
and 
And let
represent the sample mean, the distribution for the sample mean is given by:

We are interested on this probability

And the best way to solve this problem is using the normal standard distribution and the z score given by:

If we apply this formula to our probability we got this:


And we can find this probability on this way:

Answer:
A. 27.3
B. 27.28
Step-by-step explanation:
You would have to round the tenth place up because of the 8 in the hundredths place, and for the hundredth place you would have to see if the thousandths place is higher than a 5 and if not don’t round up.