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Pani-rosa [81]
3 years ago
6

A couple wants to have 5 kids. find the probability that they have at least one boy.

Mathematics
1 answer:
tangare [24]3 years ago
6 0

Probability of having at least 1 boy = 1 - the probability of having ALL girls.


P(5 girls) = (1/2)⁵ = 1/32


P(At least 1 boy) = 1 - 1/32 = 31/32


Answer: 31/32

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Read 2 more answers
Write the equation of a line perpendicular to 9xplus7yequals6 that passes through the point ​(9​,negative 7​).
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k:\ y=m_1x+b_1\\\\l:\ y=m_2x+b_2\\\\k\ ||\ l\iff m_1=m_2\\\\k\ \perp\ l\iff m_1m_2=-1

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k:\ 9x+7y=6\ \ \ |-9x\\\\7y=-9x+6\ \ \ \ |:7\\\\y=-\dfrac{9}{7}x+\dfrac{6}{9}\to m_1=-\dfrac{9}{7}\\\\l:\ y=m_2x+b\\\\l\ \perp\ k\iff-\dfrac{9}{7}m_2=-1\ \ \ \ |\cdot\left(-\dfrac{7}{9}\right)\\\\m_2=\dfrac{7}{9}\to\ l:\ y=\dfrac{7}{9}x+b

We know. The line <em>l</em> passes throught the point (9, -7). Substitute the coordinates of the poin to the equation of line<em> l </em>:

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