1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
alexgriva [62]
2 years ago
11

Write the equation of the line that goes through (-3.9, -1.4) and is PERPENDICULAR to 6x + 2y = 9

Mathematics
1 answer:
FrozenT [24]2 years ago
4 0

9514 1404 393

Answer:

  10x -30y = 3

Step-by-step explanation:

In general form, you can start by swapping the x- and y-coefficients, negating one of them. To find the new constant for the equation, substitute the values for the given point

  2x -6y = 2(-3.9) -6(-1.4)

  2x -6y = 0.6

Multiplying by 5 will make the numbers be integers, so will put the equation in standard form.

  10x -30y = 3

You might be interested in
2. Jason can put his money in a savings account and earn about 12 cents in interest this month, or he can
julsineya [31]

Answer:

12 cents

Step-by-step explanation:

opportunity cost of the next best option forgone when one alternative is chosen over other alternatives

by loaning matt the money he forgoes the opportunity to earn 12 cents in interest. this is his opportunity cost

8 0
2 years ago
Mold grows on bread and every day it doubles by the eighth day the entire bread is covered with mold when was half the bread cov
Brut [27]

Answer:

The mold will cover half the area as much are one day before it.

Step-by-step explanation:

Given:

Every day the mold on bread grows doubles

And by 8th day entire bread covered with it.

To Find:

When was half the bread covered by mold.

Solution:

It is said that area covered by mold doubles on each day

Total days taken to cover entire bread are 8

Let Area of bread be A

So Area covered (A) corresponds to 8 days with doubling.

So on previous day it should What ever area on 8th day/2

i.e A(8)/2

Similar on 6th day A(7)/2

So on 5ht day =A(6)/2 ,4th= A(5)/2,  on 3rd= A(4)/2, on 2nd=A(3)/2

On 1st =A(2)/2

So we required  Area= half of total.

<em>One day before the 8th day will be 7th day</em>

<em>on that day it will cover half are so that on next day will cover the double of the previous area consumed.</em>

4 0
3 years ago
X2-5x+10=0 is it quadratic equation? how can i identify the value of a,b,c? help
natali 33 [55]
A= 1
B= -5
C= 10

In order to figure it out, you can think about it like this..

4 0
3 years ago
Use the information to answer the following question.
trasher [3.6K]

Answer:

D is the answer

Step-by-step explanation:

For a: g(x) = 1 when x = 1, for f(x) 1^2 - 2(1) + 2 = 1, a is true.

For b: Both functions do have all real numbers for their domain, b is true

For c: the y-intercept of g(x) is x = 0, for f(x), it is 0^2 - 2(0) + 2 = 2, c is true

For d: g(3) = 7, f(3) = 3^2 - 2(3) + 2  = 5, d is false.

3 0
2 years ago
Superman bought two leggings for $25.80 each at KryptonCromie. How much did he spend?
kondor19780726 [428]

Answer:

51.6

Step-by-step explanation:

$25.80 + $25.80 =

OR

25.80 x 2.

7 0
2 years ago
Read 2 more answers
Other questions:
  • What is the inequality for 5(x+3)−8&lt;17
    10·1 answer
  • Can you guy help me how to solve the mole problem
    6·1 answer
  • What does 15 and 16 mean
    13·1 answer
  • What is 8 lb. 12 oz. − 5 lb. 5 oz. ?
    15·2 answers
  • Carmen is a professor at a local university. In collecting data on her Introduction to Business course for a year, she wants to
    5·1 answer
  • Help me if u understand this please
    9·2 answers
  • Solve the following equation using the quadratic formula.
    7·1 answer
  • Help me kkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkk
    7·1 answer
  • Which of the following statements are true about the function y = 3x?
    13·1 answer
  • The price of a gallon of unleaded gas has risen to $2.85 today. Yesterday's price was $2.80. Find the percentage increase. Round
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!