Scatter plots are an awesome way to display two-variable data (that is, data with only two variables<span>) and make predictions based on the data.</span>
Answer:
Mean for a binomial distribution = 374
Standard deviation for a binomial distribution = 12.97
Step-by-step explanation:
We are given a binomial distribution with 680 trials and a probability of success of 0.55.
The above situation can be represented through Binomial distribution;

where, n = number of trials (samples) taken = 680 trials
r = number of success
p = probability of success which in our question is 0.55
So, it means X <em>~ </em>
<em><u>Now, we have to find the mean and standard deviation of the given binomial distribution.</u></em>
- Mean of Binomial Distribution is given by;
E(X) = n
p
So, E(X) = 680
0.55 = 374
- Standard deviation of Binomial Distribution is given by;
S.D.(X) =
=
=
= 12.97
Therefore, Mean and standard deviation for binomial distribution is 374 and 12.97 respectively.
Answer:
{d,b}={4,3}
Step-by-step explanation:
[1] 11d + 17b = 95
[2] d + b = 7
Graphic Representation of the Equations :
17b + 11d = 95 b + d = 7
Solve by Substitution :
// Solve equation [2] for the variable b
[2] b = -d + 7
// Plug this in for variable b in equation [1]
[1] 11d + 17•(-d +7) = 95
[1] -6d = -24
// Solve equation [1] for the variable d
[1] 6d = 24
[1] d = 4
// By now we know this much :
d = 4
b = -d+7
// Use the d value to solve for b
b = -(4)+7 = 3
Solution :
{d,b} = {4,3}
Let Marc's age be x. If Jeanine is twice as old as Marc, then her age will be 2x. If their ages added together are 24, then you can create the following equation:
2x + x = 24
3x = 24
x = 8
Remember that x is Marc's age. So if Marc is 8, and Jeanine is twice as old, she will be 16.
The x variable, that is being multiplied.