Question

PLEASE HURRY!! What are the solutions to the system of equations?

Answer 1

Answer:

(0,6),(-2,0)

Step-by-step explanation:

The given equation are;

$y=x^2+5x+6$

and

$y=3x+6$

We equate both equations to get;

$x^2+5x+6=3x+6$

Regroup all terms on the left hand side to obtain;

$x^2+5x-3x+6-6=0$

$x^2+2x=0$

Factor;

$x(x+2)=0$

$x=0,x+2=0$

$x=0,x=-2$

We can put the values of x into any of equations preferably the linear equation to get;

$y=3(0)+6=6$, when x=0.

and

$y=3(-2)+6=0$, when x=-2.

The solutions are

(0,6),(-2,0)