Classify the following system of equations.

Mathematics

1 answer:

zubka84 [21]3 years ago

4 0

Answer:

B) consistent, dependent

Step-by-step explanation:

The given system is

45x - 30y = -90

-12x + 8y = 24

Let us make y the subject in both equations to get:

Top equation

$y = \frac{3}{2}y + 3$

Bottom equation

$y = \frac{3}{2}x + 3$

We can see that both equations are identically the same.

There is going to be infinitely many solutions.

We say the system is consistent and dependent.

The correct choice is B

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If v1 = (2,-5) and v2 = (4,-3), then the angle between the two vectors is _________. Round your answer to two decimal places.

siniylev [52]

The angle between two vectors is given by:
cos (x) = (v1.v2) / (lv1l * lv2l)
We have then:
v1.v2 = (2, -5). (4, -3)
v1.v2 = (2 * 4) + (-5 * (- 3))
v1.v2 = 8 + 15
v1.v2 = 23
We look for the vector module:
lv1l = root ((2) ^ 2 + (-5) ^ 2)
lv1l = 5.385164807
lv2l = root ((4) ^ 2 + (-3) ^ 2)
lv2l = 5
Substituting values:
cos (x) = (23) / ((5.385164807) * (5))
x = acos ((23) / ((5.385164807) * (5)))
x = 31.33 degrees
Answer:
The angle between the two vectors is:
x = 31.33 degrees

3 0

2 years ago

URGENT!!! Please answer ASAP with full working out thank you

Tema [17]

Step-by-step explanation:

$a) \\ \frac{a}{x - 1} - \frac{2}{x + 1} = \frac{4}{(x - 1)(x + 1)} \\ \\ \frac{a(x + 1) - 2(x - 1)}{(x - 1)(x + 1)} = \frac{4}{(x - 1)(x + 1)} \\ \\ a(x + 1) - 2x + 2 = 4 \\ \\ a(x + 1) = 4 + 2x - 2 \\ \\ a(x + 1) = 2x + 2 \\ \\ a (x + 1) = 2(x + 1) \\ \\ a= \frac{2(x + 1)}{(x + 1)} \\ \\ \huge \red{ \boxed{a = 2}}$