Answer:
a)1400 + 300x ≤ 5000
b) x ≤ 12 days
Step-by-step explanation:
a) Since the grocery store owner wants to stay within budget then, this means he would be spending at most $5,000
The word at most is represented by the inequality sign ≤ = Less than or equal to
Let x = Number of days
Hence,
Our inequality equation is
$1400 + 300× x ≤ $5000
1400 + 300x ≤ 5000
b) Solving for x
1400 + 300x ≤ 5000
300x ≤ 5000 - 1400
300x ≤ 3600
x ≤ 3600/300
x ≤ 12 days
Answer:
d=30-5c/2
Step-by-step explanation:
Move all terms that don't contain d to the right side and solve
Answer:
After finding the prime factorization of $2010=2\cdot3\cdot5\cdot67$, divide $5300$ by $67$ and add $5300$ divided by $67^2$ in order to find the total number of multiples of $67$ between $2$ and $5300$. $\lfloor\frac{5300}{67}\rfloor+\lfloor\frac{5300}{67^2}\rfloor=80$ Since $71$,$73$, and $79$ are prime numbers greater than $67$ and less than or equal to $80$, subtract $3$ from $80$ to get the answer $80-3=\boxed{77}\Rightarrow\boxed{D}$.
Step-by-step explanation:
hope this helps
Question:
The local community theater sold a total of 240 tickets for Saturday night’s performance. They sold 180 more full-price tickets than discount tickets. Which system of equations can be used to model this situation?
Answer:
Step-by-step explanation:
Given
Represent the number of full price with x and discounted price with y.
From the question:
x = 180 more than y
So:
Also, a total of 240 were sold.
So:
Hence, the equations are:
Solving further;
Substitute 180 + y for x in
Solve for 2y
Divide through by 2
Recall that:
Hence:
<em>Full Price = 210</em>
<em>Discounted = 30</em>
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