I REALLY NEED HELP WITH THESE FIVE MATH QUESTIONS WILL LIKE RATE AND MARK BRAINLIEST
1 answer:
Answer:
Just took the test and got the correct answers!!
Step-by-step explanation:
For the 1st and 4th question: look at the first and second image down below for the answer *\(♡°▽°♡)/*
2nd question:
x= 67.5 (for reasoning look at the third picture)
3rd question:
x= 41 (for reasoning look at the fourth picture)
5th question:
x= 39 (for reasoning look at the fifth picture)
<em>I hope this helps!! ♡＼(￣▽￣)／♡ Best of luck!!</em>
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The triangles are drawn in the picture attached.
Let's call M the intersection point of AB and CD. Since CD is the perpendicular bisector, we know that:
AM ≡ MB (bisector = divides into two equal pieces)
∠AMD ≡ ∠AMC ≡ ∠BMC ≡ ∠BMD (perpendicular = forms 4 angles of 90°)
Considering ΔAMD and ΔBMD, they have also MD in common, therefore, we can use the SAS (side - angle - side) congruency criterium to prove that they are congruent.
Similarly for ΔAMC and ΔBMC.
Therefore, <span>ΔADC ≡ ΔBCD because they are made of congruent triangles.</span>
Hence, with the SAS congruency theorem, we can demonstrate that ΔADC ≡ ΔBCD
Let's call M the intersection point of AB and CD. Since CD is the perpendicular bisector, we know that:
AM ≡ MB (bisector = divides into two equal pieces)
∠AMD ≡ ∠AMC ≡ ∠BMC ≡ ∠BMD (perpendicular = forms 4 angles of 90°)
Considering ΔAMD and ΔBMD, they have also MD in common, therefore, we can use the SAS (side - angle - side) congruency criterium to prove that they are congruent.
Similarly for ΔAMC and ΔBMC.
Therefore, <span>ΔADC ≡ ΔBCD because they are made of congruent triangles.</span>
Hence, with the SAS congruency theorem, we can demonstrate that ΔADC ≡ ΔBCD