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melomori [17]
3 years ago
15

You

Computers and Technology
2 answers:
N76 [4]3 years ago
8 0

Answer: A

Explanation: the process or action of verifying the identity of a user or process.

Hope this helps ^.^

Scilla [17]3 years ago
7 0

The Answer would be (A. Authentication) it’s how they find out the authenticity of your identity before they let you in.

Let us know is there is any thing else you need to know.

Mark brainlest :)

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Give two examples of non printing characters
VMariaS [17]
Space — each pressing of the key will be displayed as ·
Non-breaking space (°) is a space character that prevents an automatic line break at its position.
3 0
3 years ago
Which elements are visible when a user opens a new PowerPoint presentation?
Mariulka [41]

Answer:

The only element visible is the presentation itself.

Explanation:

All of the other options, such as presenter's assistance, is hidden away from the projector, presentation device, etc. You are the only one that can see the window that shows what slide is next, presenter's notes, etc. <u>In other words, whatever you want the audience to see, that is only what they will see and nothing else.</u>

3 0
2 years ago
Read 2 more answers
Create a class called Hokeemon that can be used as a template to create magical creatures called Hokeeemons. Hokeemons can be of
Viefleur [7K]

Answer:

See Explaination

Explanation:

/*****************************************Hokeemon.java********************************/

import java.io.File;

import java.io.FileNotFoundException;

import java.util.Scanner;

public class Hokeemon {

private String name;

private String type;

private int age;

public Hokeemon(String name, String type, int age) {

super();

this.name = name;

this.type = type;

this.age = age;

}

public Hokeemon() {

this.name = "";

this.type = "";

this.age = 0;

}

public String getName() {

return name;

}

public void setName(String name) {

this.name = name;

}

public String getType() {

return type;

}

public void setType(String type) {

this.type = type;

}

public int getAge() {

return age;

}

public void setAge(int age) {

this.age = age;

}

public String liveIn() {

if (this.type.equalsIgnoreCase("dwarf")) {

return "Mountain";

} else if (this.type.equalsIgnoreCase("elf")) {

return "Dale";

} else if (this.type.equalsIgnoreCase("fairy")) {

return "Forest";

} else {

return "Shire";

}

}

public boolean areFriends(Hokeemon other) {

if (this.type.equalsIgnoreCase(other.type)) {

return true;

} else if ((this.type.equalsIgnoreCase("dwarf") && other.type.equalsIgnoreCase("elf"))

|| (this.type.equalsIgnoreCase("elf") && other.type.equalsIgnoreCase("dwarf"))) {

return true;

} else if ((this.type.equalsIgnoreCase("hobbit") && other.type.equalsIgnoreCase("fairy"))

|| (this.type.equalsIgnoreCase("fairy") && other.type.equalsIgnoreCase("hobbit"))) {

return true;

} else {

return false;

}

}

public static Hokeemon[] getData(String file) {

Hokeemon[] hokeemons = new Hokeemon[8];

int i = 0;

try {

Scanner scan = new Scanner(new File(file));

while (scan.hasNextLine() && i < hokeemons.length) {

String line = scan.nextLine();

String[] data = line.split("\\s+");

String name = data[0];

String type = data[1];

int age = Integer.parseInt(data[2]);

hokeemons[i] = new Hokeemon(name, type, age);

i++;

}

scan.close();

} catch (FileNotFoundException e) {

System.err.println(e);

}

return hokeemons;

}

public static String getBio(Hokeemon[] hokeemons) {

String s = "";

for (Hokeemon hokeemon : hokeemons) {

s += "I am " + hokeemon.getName() + ": Type " + hokeemon.getType() + ": Age=" + hokeemon.getAge()

+ ", I live in " + hokeemon.liveIn() + "\n";

s += "My friends are: ";

for (Hokeemon hokeemon2 : hokeemons) {

if (hokeemon.areFriends(hokeemon2) && !hokeemon.equals(hokeemon2)) {

s += (hokeemon2.getName() + " ");

}

}

s += "\n";

}

return s;

}

atOverride

public String toString() {

return "Name " + name + ": Type " + type + ": Age=" + age + "\n";

}

}

/*******************************HokeemonMain.java**************************/

import java.util.Arrays;

public class HokeemonMain {

public static void main(String[] args) {

Hokeemon[] hokeemons = Hokeemon.getData("data.txt");

System.out.println(Arrays.toString(hokeemons));

System.out.println(Hokeemon.getBio(hokeemons));

}

}

/**********************************data.txt********************/

Noddy Dwarf 4

Legolas Elf 77

Minerva Fairy 33

Samwise Hobbit 24

Merry Hobbit 29

Warhammer Dwarf 87

Ernedyll Elf 19

Frodo Hobbit 18

3 0
3 years ago
Write an algorithm to find perimeter of circle<br>​
Anna11 [10]

Answer:

Here’s one!

Given [math]R[/math], the radius of the circle.

Let [math]N,D\leftarrow 0[/math]

Repeat until [math]D[/math] is large enough (about 1,000,000)

[math]x,y\leftarrow U[0,1][/math]

If [math]x^2 + y^2\le 1[/math] then [math]N\leftarrow N+1[/math]

[math]D\leftarrow D+1[/math]

[math]P\leftarrow\frac{8NR}{D}[/math]

Return [math]P[/math]

[math]U[0,1][/math] is a uniform random number in the range [math][0,1][/math].

Explanation:

6 0
2 years ago
What is the numerical ratio that is equivalent to 19.2 dB?
mrs_skeptik [129]

Answer: 83.17

Explanation:

By definition, the dB is an adimensional unit, used to simplify calculations when numbers are either too big or too small, specially in telecommunications.

It applies specifically to power, and it is defined as follows:

P (dB) = 10 log₁₀ P₁ / P₂

Usually P₂ is a reference, for instance, if P₂ = 1 mW, dB is called as dBm (dB referred to 1 mW), but it is always adimensional.

In our question, we know that we have a numerical ratio, that is expressed in dB as 19.2 dB.

Applying the dB definition, we can write the following:

10 log₁₀ X = 19.2 ⇒ log₁₀ X = 19.2 / 10 = 1.92

Solving the logarithmic equation, we can compute X as follows:

X = 10^1.92  = 83.17

X = 83.17

4 0
3 years ago
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