A. How many kilowatt hours of electricity did the Smiths use during February?
Kilowatt hours of electricity the Smiths used during February:
Meter read on March 1 - meter read on February 1 =
20,288 kilowatt hours - 19,423 kilowatt hours =
865 kilowatt hours
Answer: The Smiths used 865 kilowatt hours of electricity during February
b. How many kilowatt hours did they use during March?
Kilowatt hours of electricity the Smiths used during March:
Meter read on April 1 - meter read on March 1 =
21,163 kilowatt hours - 20,288 kilowatt hours =
875 kilowatt hours
Answer: The Smiths used 875 kilowatt hours of electricity during March
Answer:
Hey mate here is your answer...
Step-by-step explanation:
smaller circular table to be made
with a diameter only half as big... and diameter of big table is (2*55)= 110cm.... So half diameter of big is (110/2)= 55cm
therefore, diameter of smaller table is 55cm and radius of it's (55/2)= 27.5cm
circumference of circle = 2πr
= 2*3.14*27.5
= 172.7 cm = 27.5cm
hope it helps you ❣️
Answer:
-1
Step-by-step explanation:
The required relation is ...
7n = n^2 -8
0 = n^2 -7n -8 . . . . put in standard form
0 = (n -8)(n +1) . . . . factor
Solutions are n=8 and n=-1.
The negative solution is -1.
Answer:
<em>-21 and 4</em>
Step-by-step explanation:
They multiply to a negative number, so you need a positive number and a negative number.
