Answer:
g = 1, 3
General Formulas and Concepts:
<u>Pre-Algebra</u>
<u>Algebra I</u>
- Terms/Coefficients
- Factoring
- Solving quadratics
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
g² - 4g = -3
<u>Step 2: Solve for </u><em><u>g</u></em>
- [Addition Property of Equality] Add 3 on both sides: g² - 4g + 3 = 0
- Factor: (g - 1)(g - 3) = 0
- Solve: g = 1, 3
Answer:
A
Step-by-step explanation:

as 0≤θ≤90
so θ/2 is also in 0≤θ≤90
hence sin θ/2 and cos θ/2 are positive.
Answer:
just took the test, it is NOT c.
Step-by-step explanation:
for the value of
we have the function f(x) = 1/(x-2) or
as undefined or not defined .
<u>Step-by-step explanation:</u>
<u>Function undefined: </u> A function is undefined when it gives results which are not defined for example , infinity .
Here we have , Function f(x) = 1/(x-2) or
. We need to find a value of for which this is not defined . Let's find out:
We can clearly see that it's a fractional function with numerator as 1 and denominator as x-2 . For a fractional function to be undefined it's denominator must be zero i.e. x-2 = 0 or 
⇒ 
⇒ 
⇒ 
Therefore, for the value of
we have the function f(x) = 1/(x-2) or
as undefined or not defined .
Part a. 6x +3y = 15
3y = 15 -6x
y = 5 - 2x
Part b. y = 1
Part c. y = -5