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3 years ago

Answer plssss????????

Mathematics

1 answer:

san4es73 [151]3 years ago

5 0

Answer:

Step-by-step explanation:

y=22x+10

y is the total spent

the tickets are 22. 22x is the amount of 22 the x is the number of tickets bought. we don't know this, so it's x. the 10 is the parking fee.

Example:

If 4 people go to the game, the equation would be:

22(4)+10=

88+10=98

22 a ticket by 4 people+10 for parking=98.

The x is a variable since we don't know that number of tickets bought. The parking fee of 10.00 will not change since this is a one-time charge.

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Square root of 2tanxcosx-tanx=0

kobusy [5.1K]

If you're using the app, try seeing this answer through your browser: brainly.com/question/3242555

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Solve the trigonometric equation:

$\mathsf{\sqrt{2\,tan\,x\,cos\,x}-tan\,x=0}\\\\ \mathsf{\sqrt{2\cdot \dfrac{sin\,x}{cos\,x}\cdot cos\,x}-tan\,x=0}\\\\\\ \mathsf{\sqrt{2\cdot sin\,x}=tan\,x\qquad\quad(i)}$

Restriction for the solution:

$\left\{ \begin{array}{l} \mathsf{sin\,x\ge 0}\\\\ \mathsf{tan\,x\ge 0} \end{array} \right.$

Square both sides of (i):

$\mathsf{(\sqrt{2\cdot sin\,x})^2=(tan\,x)^2}\\\\ \mathsf{2\cdot sin\,x=tan^2\,x}\\\\ \mathsf{2\cdot sin\,x-tan^2\,x=0}\\\\ \mathsf{\dfrac{2\cdot sin\,x\cdot cos^2\,x}{cos^2\,x}-\dfrac{sin^2\,x}{cos^2\,x}=0}\\\\\\ \mathsf{\dfrac{sin\,x}{cos^2\,x}\cdot \left(2\,cos^2\,x-sin\,x \right )=0\qquad\quad but~~cos^2 x=1-sin^2 x}$

$\mathsf{\dfrac{sin\,x}{cos^2\,x}\cdot \left[2\cdot (1-sin^2\,x)-sin\,x \right]=0}\\\\\\ \mathsf{\dfrac{sin\,x}{cos^2\,x}\cdot \left[2-2\,sin^2\,x-sin\,x \right]=0}\\\\\\ \mathsf{-\,\dfrac{sin\,x}{cos^2\,x}\cdot \left[2\,sin^2\,x+sin\,x-2 \right]=0}\\\\\\ \mathsf{sin\,x\cdot \left[2\,sin^2\,x+sin\,x-2 \right]=0}$

Let

$\mathsf{sin\,x=t\qquad (0\le t$

So the equation becomes

$\mathsf{t\cdot (2t^2+t-2)=0\qquad\quad (ii)}\\\\ \begin{array}{rcl} \mathsf{t=0}&\textsf{ or }&\mathsf{2t^2+t-2=0} \end{array}$

Solving the quadratic equation:

$\mathsf{2t^2+t-2=0}\quad\longrightarrow\quad\left\{ \begin{array}{l} \mathsf{a=2}\\ \mathsf{b=1}\\ \mathsf{c=-2} \end{array} \right.$

$\mathsf{\Delta=b^2-4ac}\\\\ \mathsf{\Delta=1^2-4\cdot 2\cdot (-2)}\\\\ \mathsf{\Delta=1+16}\\\\ \mathsf{\Delta=17}$

$\mathsf{t=\dfrac{-b\pm\sqrt{\Delta}}{2a}}\\\\\\ \mathsf{t=\dfrac{-1\pm\sqrt{17}}{2\cdot 2}}\\\\\\ \mathsf{t=\dfrac{-1\pm\sqrt{17}}{4}}\\\\\\ \begin{array}{rcl} \mathsf{t=\dfrac{-1+\sqrt{17}}{4}}&\textsf{ or }&\mathsf{t=\dfrac{-1-\sqrt{17}}{4}} \end{array}$

You can discard the negative value for t. So the solution for (ii) is

$\begin{array}{rcl} \mathsf{t=0}&\textsf{ or }&\mathsf{t=\dfrac{\sqrt{17}-1}{4}} \end{array}$

Substitute back for t = sin x. Remember the restriction for x:

$\begin{array}{rcl} \mathsf{sin\,x=0}&\textsf{ or }&\mathsf{sin\,x=\dfrac{\sqrt{17}-1}{4}}\\\\ \mathsf{x=0+k\cdot 180^\circ}&\textsf{ or }&\mathsf{x=arcsin\bigg(\dfrac{\sqrt{17}-1}{4}\bigg)+k\cdot 360^\circ}\\\\\\ \mathsf{x=k\cdot 180^\circ}&\textsf{ or }&\mathsf{x=51.33^\circ +k\cdot 360^\circ}\quad\longleftarrow\quad\textsf{solution.} \end{array}$

where k is an integer.

I hope this helps. =)

3 0

3 years ago

Find the volume of a square pyramid with a base area of 18inch squared and the height of 4 inches

den301095 [7]

Vpyramid=1/3 times area of base times height
volume=1/3 times 18 square inches times 4in
volume=6 square inches times 4in
volume=24 cubic inches

the volume is 24 cubic inches

5 0

2 years ago

Sandra is putting up a fence around her garden, which is in the shape of a square. Each foot of fencing costs $9. If each side o

mestny [16]

Answer:

Sandra will need 32 feet of fencing. This is because the shape of the garden is a square. The length is 8 ft, so the perimeter of the garden is 32.

Step-by-step explanation:

4 0

3 years ago

Suppose 232subjects are treated with a drug that is used to treat pain and 50of them developed nausea. Use a 0.01significance le

Margarita [4]

Answer:

The correct option is B

$t = 0.6093$

$p-value = 0.27116$

The correct option is D

Step-by-step explanation:

From the question we are told that

The sample size is $n = 232$

The number that developed nausea is X = 50

The population proportion is p = 0.20

The null hypothesis is $H_o : p = 0.20$

The alternative hypothesis is $H_a : p > 0.20$

Generally the sample proportion is mathematically represented as

$\r p = \frac{50}{232}$

$\r p = 0.216$

Generally the test statistics is mathematically represented as

=> $t = \frac{\r p - p }{ \sqrt{ \frac{p(1- p )}{n} } }$

=> $t = \frac{ 0.216 - 0.20 }{ \sqrt{ \frac{ 0.20 (1- 0.20 )}{ 232} } }$

=> $t = 0.6093$

The p-value obtained from the z-table is

$p-value = P(Z > 0.6093) = 0.27116$

Given that the $p-value > \alpha$ then we fail to reject the null hypothesis

5 0

3 years ago

Divergent and Convergent sums

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<span>The infinite growth of the trees is represented by ∑ form n = 1 to infinity of 200(1.2)^n.

The sum is cannot be found because the series is divergent.
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7 0

3 years ago

Answer plssss????????​

Answer plssss????????