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3 years ago

Solve for x.. 12x + 7 < -11 OR 5x – 8 > 40

Mathematics

1 answer:

krok68 [10]3 years ago

7 0

Answer:

x>48/5 or x<-3/2

Step-by-step explanation:

Solve for x

a) 12x + 7 < -11

12x < -11-7

12x < -18

x < -18/12

⇒ Simplify: divide the numerator by 6

x < -3/2

b) 5x – 8 > 40

5x > 40+8

5x > 48

x > 48/5

Therefore, x>48/5 or x<-3/2.

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Step-by-step explanation:

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2 years ago

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Find the tangent line equation of the curve at the given point. Y=arcsin(7x) at the point where x=sqrt2/14

Mumz [18]

Answer:

$Y-\frac{\pi}{2} =\frac{\pi}{2} (x+\sqrt{\frac{1}{7}})$

Step-by-step explanation:

The equation of the curve is

$Y = sin^{-1}(7x)$

To find the equation of tangent we need to differentiate this equation w.r.t x

So, differentiating we get

$Y'=\frac{7}{\sqrt{1-49x^2} }$

This would give the slope of the tangent line at any given point of which x coordinate is known. In the present case it is $x = \sqrt{\frac{1}{7} }$

Then slope would accordingly be

$Y'=\frac{7}{\sqrt{1-49/49} }$

= ∞

For, $x = \sqrt{\frac{1}{7} }$ , $Y = sin^{-1}(7/7)= \pi/2$

Equation of tangent line, in the point slope form, would be $Y-\frac{\pi}{2} =\frac{\pi}{2} (x+\sqrt{\frac{1}{7}})$

4 0

2 years ago

-3/4 + (-3/4) <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B%20-%203%7D%7B4%7D%20%20%2B%20%20%5Cfrac%7B%20-%203%7D%7B4%7D%20

nika2105 [10]

Firstly, since these two fractions have the same denominator, add the numerators up: $\frac{-6}{4}$

While it appears that the answer is -6/4, you can further simplify it by dividing the numerator and denominator by 2: $-\frac{6}{4}\div\frac{2}{2}=-\frac{3}{2}$

Your answer is $-\frac{3}{2}$ 

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3 years ago

Which inequality has no solution? 6(x+2) > x-3 3+4x2(1+ 2x) -2(x+6) X-9 <3(x-3)

Juli2301 [7.4K]

Answer:

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$6x + 12 > x - 3$

$6x - x > - 12 - 3$

$5x > - 9$

$3 + 4 \times 2(1 + 2x)$

$3 + 8(1 + 2x)$

$3 + 8 + 16x$

$11 + 16x$

$- 2(x + 6)x - 9 < 3(x - 3)$

$- 2( {x}^{2} + 6x) - 9 < 3x - 9$

$- 2 {x}^{2} - 12x - 9 < 3x - 9$

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2 years ago

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Whitepunk [10]

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2 years ago