Answer:
37/60 OR 111/180
(37/60 is simplified and 111/180 is the original)
Complete question:
Consider 3 boxes, each of which contains 4 balls in particular, box 1 contains 4 white balls, box 2 contains 3 white balls and 1 red ball, box 3 contains 2 white balls and 2 red balls. Frank chooses a box at random. If boxes 1 and 3 are chosen, Frank extracts 2 balls without replacement. If box 2 is chosen Frank extracts 2 balls with replacement. USE ONLY THE CONDITIONAL PROBABILITY FORMALISM and derive an expression for the probability that the 2 extracted balls are red.
Answer:
11/288
Step-by-step explanation:
We are given:
Box 1: ( 4White, ORed)
Box 2: (3White, 1Red)
Box 3: (2White, 2 Red)
We are told that if Frank choose from Box 1 and Box 3, 2 balls are extracted without replacement.
Since there is no red ball in Box 1, there is no way 2 red balls will come out from Box1.
Our Event, E = getting 2 red balls.
Now Box 1 is ruled out, we have:
P[E(B1)]= 0
P[E/B3)] = (2 2) / (4 2)
= 1/6
If box 2 is chosen, 2 balls are extracted with replacement. Therefore for Box 2:
P(E/B2) = (1/4) *(1/4)
= 1/16
Therefore probability that 2 balls extracted are red, we have:
P(E)=P(E/B1) P(B1) + P(E/B2) P(B2)+P(E/B3) P(B3)

= 11/288
-sin(-x)/cos(-x)*cos(-x)/sin(-x)
Simplifying, we get 1
Answer: 
Step-by-step explanation:
<u>Given information</u>
Paid = $15.00 / hour
Paid (Last 4 hours) = Doubled the usual pay rate
Total hour = 12 hours
<u>Given expression</u>
Wage = Pay rate × hours except for the last 4 hours + Double Pay rate × 4 hours
<u>Substitute values into the expression</u>
Wage = (15) × (12 - 4) + (15 × 2) × (4)
<u />
<u>Simplify values in the parenthesis</u>
Wage = 15 × 8 + 30 × 4
<u>Simplify by multiplication</u>
Wage = 120 + 120
<u>Simplify by addition</u>

Hope this helps!! :)
Please let me know if you have any questions