Answer:
m∠AEC = 139°
Step-by-step explanation:
To make the equations easier to write, let's say all measures are in degrees, and define ...
p = m∠AEB = 11x -12
q = m∠CED = m∠CEB = 4x +1
Then ...
p + 2q = 180
(11x -12) + 2(4x +1) = 180
19x -10 = 180 . . . . . . . . . . . . collect terms
19x = 190 . . . . . . . . add 10
x = 10 . . . . . . . . . . . divide by 19
p = 11x -12 = 110 -12 = 98
q = 40 +1 = 41
The angle of interest is ...
m∠AEC = p +q = 98 +41
m∠AEC = 139 . . . . degrees
Answer:
3 bars
Step-by-step explanation:
Total no. of gold bars = 24.
Fraction of bar captain allocated to himself = 1/3 of the bars
no. of bars he allocated to himself = 1/3 of 24 = 1/3 * 24 = 8
Fraction of bar captain allocated to his friend bill = 1/4 of the bars
no. of bars he allocated to his friend bill = 1/4 of 24 = 1/4 * 24 = 6
No . of bars captain allocated to rest of crew = 7
Total no of bars which are allocated altogether =
no. of bars he allocated to himself +no. of bars he allocated to his friend bill +No . of bars captain allocated to rest of crew
substituting the value of above summation variable as calculated above we have
Total no of bars which are allocated altogether = 8+6+7 = 21
No. of bars left = total no. of bars - Total no of bars which are allocated altogether = 24 - 21 = 3
Thus 3 gold bars are left.
Answer:
The slope of the line through (−9,6) and (−6,−9) is −5
Step-by-step explanation:
Hope it helps
You didnt show the rest of the picture i can't help if i can't see.
