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djyliett [7]
3 years ago
5

Can somebody help me. i don't know if these are right or wrong. If they're wrong can you please correct me? appreciate it​

Mathematics
2 answers:
Alenkinab [10]3 years ago
8 0
You wrote 35300 instead of 45300 for question 5.
notsponge [240]3 years ago
3 0

Step-by-step explanation:

it is right

all are right

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I need help once more (●'◡'●)
Luden [163]

Answer:

3= 25 4= 20 25= 5

Step-by-step explanation:

its a pattern. the top goes up by ones and the bottom goes up by fives.

7 0
3 years ago
10 times 100 fhg[';g;8utfdkibjlif
adoni [48]

Answer:

1,000 nmvfdmld

Step-by-step explanation:

5 0
3 years ago
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I need this ASAP!!<br><br><br> calculate the rate of change on this graph
Vilka [71]

Answer: The slope is 2

Step-by-step explanation: For questions like these, find 2 points on the graph that are on whole numbers, for example (10,60) and (20,80). Then use the formula y2-y1/x2-x1 to solve for the slope, which would be the same thing as rate of change. 80-60/20-10 which equals 2. The slope would be 2.

8 0
3 years ago
harvard university accepts 6 student for every 100 applications.how many students will be accepted if 850 applicants apply for a
Oksanka [162]
6\100 also equals 3/50

so in turn if 50 goes into 850 exactly 17 times we can then multiply 6 by that same variable

in turn if there were 850 applicants then 102 students would be accepted into Harvard.
6 0
3 years ago
Read 2 more answers
The domain of ​(f​g)(x) consists of the numbers x that are in the domains of both f and g.
Dovator [93]

The statement "The domain of (fg)(x) consists of the numbers x that are in the domains of both f and g" is FALSE.

Domain is the values of x in the function represented by y=f(x), for which y exists.

THe given statement is "The domain of (fg)(x) consists of the numbers x that are in the domains of both f and g".

Now we assume the g(x)=x+2 and f(x)=\frac{1}{x-6}

So here since g(x) is a polynomial function so it exists for all real x.

f(x)=\frac{1}{x-6}<em>  </em>does not exists when x=6, so the domain of f(x) is given by all real x except 6.

Now,

(fg)(x)=f(g(x))=f(x+2)=\frac{1}{(x+2)-6}=\frac{1}{x-4}

So now (fg)(x) does not exists when x=4, the domain of (fg)(x) consists of all real value of x except 4.

But domain of both f(x) and g(x) consists of the value x=4.

Hence the statement is not TRUE universarily.

Thus the given statement about the composition of function is FALSE.

Learn more about Domain here -

brainly.com/question/2264373

#SPJ10

3 0
1 year ago
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