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Natalija [7]
3 years ago
12

Exponents how do you do them

Mathematics
2 answers:
konstantin123 [22]3 years ago
7 0
 3 to the power of 5 
 
 you multiply 3 times 5 instead of 3 times 3 times 3 times 3  times 3  
<span />
xxMikexx [17]3 years ago
5 0
Say the equation is 5 to the 2nd power +7 you would multiply the 5x2 which is 10 then + 7 =17
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Find the zeros of the function. Write the smaller solution first, and the larger solution second. f(x)=(x+8)^2−1
BartSMP [9]

Answer:

zeroes: x = -9 and x = -7

Step-by-step explanation:

f(x)=(x+8)^2−1

A "zero" refers to when the y-value on the graph is zero.

0 = (x+8)^2 - 1

1 = (x+8)^2

+ or - 1 = x+8

so break them apart into two equations

x+8 = 1  OR  x+8 = -1

x = -7  OR  x = -9

You can plug both back in to check that the equation works!

4 0
3 years ago
Help asappppp? i’m having trouble on wat the 1/4 point is
blagie [28]

Answer:

  (-14, 5.5)

Step-by-step explanation:

Perhaps the easiest way to find the 1/4 point is to find (x, y), then find the midpoint between that and M.

  (x, y) = 2M -(13, 25) = 2(-5, 12) -(13, 25) = (-23, -1)

Then the 1/4 point is ...

  ((-23, -1) +M)/2 = ((-23, -1) +(-5, 12))/2 = (-28, 11)/2 = (-14, 5.5)

_____

If we call the end points A(x, y) and B(13, 25), then we know ...

  M = (A+B)/2

  A = 2M -B . . . . we'll need this in a bit

and the 1/4 point Q is such that ...

  (Q -A)/(B -A) = 1/4

  4Q -4A = B -A . . . . cross multipliy

  Q = (B +3A)/4 = (B +3(2M -B))/4 = (6M -2B)/4 . . . . solve for Q

  Q = (3M -B)/2 . . . . reduce the fractions

  Q = (3(-5, 12) -(13, 25))/2 = (-28, 11)/2 = (-14, 5.5) . . . as above

6 0
3 years ago
A car requires 22 litres of petrol to travel a distance of 259.6 km.Find
Anon25 [30]

Answer:

Step-by-step explanation:

1. A car requires 22 litres of petrol to travel a distance of 259.6 km

what is the distance that the car can travel on 63 ltr of petrol

22ltr = 259.6km

63ltr=

cross multiply

{63 x 259.6}/22 = 16354.8/22 = 743.4 km

A car requires 22 litres of petrol to travel a distance of 259.6 km, it would require 63 ltr of petrol to travel 743.4km

2. To travel a distance of 2013.2 km

we would need to calculate the amount of fuel

A car requires 22 litres of petrol to travel a distance of 259.6 km

what amount of fuel would it require to travel 2013.2km

22ltr = 259.6km

xltr = 2013.2km

x is the value of petrol to cover 2013.2km

cross multiply

(2013.2 x 22)/259.6

44290.4/259.6 = 170.610169492≈170.6 ltr

A car requires 22 litres of petrol to travel a distance of 259.6 km, it would require 170.6 ltr of petrol to travel 2013.2km

if 1ltr is $1.99

170.6 ltr is (170.6 x 1.99)/1 = $339.494≈$339.5

The price of fuel consumed for 2013.2 km at 1 liter of petrol at $1.99 is $339.5

5 0
3 years ago
I spent $10 dollars out $25 what is percent I spent
Lina20 [59]
\text {Percentage spent = }  \dfrac{10}{25} \times 100

\text {Percentage spent = }  \dfrac{2}{5} \times 100

\text {Percentage spent = }  40 \%
3 0
3 years ago
Read 2 more answers
Find the value of n that makes equation true.<br> 5n =20<br> n + 5 = 10<br> 2n = 3<br> n + 5 = 13
Kamila [148]

Answer:

n+5=10

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
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