Question

A study conducted on 40,000 words in the English language found that about 6,670 words started with the letter T, which is the most common letter to start a word. If we randomly pick 20 unique words, which of these lists of words will come closest to the theoretical probability of getting a word beginning with T?

Answer 1

Answer:

Required Probability=$\frac{^{6670}C_{20}}{^{40000}C_{20}}$

Step-by-step explanation:

We have been given the total  40,000 words

And the words that started with letter T is 6,670

We need to find the probability of the words beginning with T

Words beginning with T will be $^{6670}C_{20}$

Total words after choosing 20 unique words would be: $^{40000C_{20}$

$Probability=\frac{\text{words beginning with T}}{\text{total words}}$

$Probability=\frac{^{6670}C_{20}}{^{40000}C_{20}}$

Hence,

Required Probability=$\frac{^{6670}C_{20}}{^{40000}C_{20}}$

Answer 2

Answer:

$\frac{^{6670}C_{20}}{^{40000}C_{20}}$

Step-by-step explanation:

Given : A study conducted on 40,000 words in the English language found that about 6,670 words started with the letter T, which is the most common letter to start a word.

To Find: If we randomly pick 20 unique words, which of these lists of words will come closest to the theoretical probability of getting a word beginning with T?

Solution:

There are 6670 words starting from T

They randomly select 20 words

So, the possible outcomes starting from T : $^{6670}C_{20}$

Since 20 words are selected from the total of 40000: $^{40000}C_{20}$

So, probability of getting a word beginning with T : $\frac{^{6670}C_{20}}{^{40000}C_{20}}$