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uysha [10]
4 years ago
14

29. A painter leans a ladder against the side of a

Mathematics
2 answers:
Reika [66]4 years ago
6 0

Answer:

16.2788 feet

Step-by-step explanation:

a²+b²=c²

3²+16²=c²

9+256=c²

265=c²

c=√265

c=16.2788 feet

Lerok [7]4 years ago
5 0

Answer:

16.3 feet (to the nearest tenth)

Step-by-step explanation:

Use Pythagoras theorem

Length = sqrt(3^2+16^2) = sqrt(9+256) = sqrt(265) = 16.3 ft.

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How many bowls of cereal did he eat pls and thx​
miv72 [106K]

36 bowls - since with one gallon he can eat 12 bowls (as demonstrated by 1/12), you multiply 12 by 3 to get 36 bowls.

8 0
4 years ago
Read 2 more answers
3. The area of a square garden is 200 m2. How long is the diagonal?
Step2247 [10]

The answer and explanation in the pic below

Good luck,!

If helped..mark brainliest please ;)

3 0
3 years ago
An educational psychologist wishes to know the mean number of words a third grader can read per minute. She wants to make an est
nirvana33 [79]

Answer:

The 80% confidence interval for the mean number of words a third grader can read per minute is between 40.4 wpm and 40.8 wpm.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.8}{2} = 0.1

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.1 = 0.99, so z = 1.28

Now, find M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.28*\frac{4.1}{\sqrt{840}} = 0.2

The lower end of the interval is the sample mean subtracted by M. So it is 40.6 - 0.2 = 40.4 words per minute.

The upper end of the interval is the sample mean added to M. So it is 40.6 + 0.2 = 40.8 words per minute.

The 80% confidence interval for the mean number of words a third grader can read per minute is between 40.4 wpm and 40.8 wpm.

3 0
4 years ago
Manny bought a brand new car in 2012 for $28,750. If the car depreciates by 12% each year, write an exponential function to mode
patriot [66]
The exponential formula for this situtation will be given by:
f(x)=ae^(-bx)
where:
a=initial price
b=rate
x=time in years
hence the formula will be:
f(x)=28750e^(-0.12x)
thus the value of the car in 2018 will be:
x=2018-2012=6 years
thus
f(6)=28750e^(-0.12*6)
f(6)=$13,994.13
5 0
3 years ago
An automobile manufacturer would like to know what proportion of its customers are not satisfied by the service provided by the
zheka24 [161]

Answer:

The sample size needed if the margin of error of the confidence interval is to be about 0.04 is 18.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

Past studies suggest this proportion will be about 0.15

This means that p = 0.15

Find the sample size needed if the margin of error of the confidence interval is to be about 0.04

This is n when M = 0.04. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.04 = 1.96\sqrt{\frac{0.15*0.85}{n}}

0.04\sqrt{n} = 1.96\sqrt{0.15*0.85}

\sqrt{n} = \frac{1.96\sqrt{0.15*0.85}}{0.04}

(\sqrt{n})^{2} = (\frac{1.96\sqrt{0.15*0.85}}{0.04})^{2}

n = 17.5

Rounding up

The sample size needed if the margin of error of the confidence interval is to be about 0.04 is 18.

8 0
3 years ago
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