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aleksley [76]
3 years ago
13

Which functions are decreasing? Select ALL answers that are correct.

Mathematics
2 answers:
adoni [48]3 years ago
6 0
Among all the diagrams, Function 1 and 4 is decreasing

Hope this helps!
Ne4ueva [31]3 years ago
4 0
1.              2.       1 and 3 are decreasing


3.              4.
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In a month with 31 days, Google featured Doodles on 18 days.What percent of the month was this?Round to the nearest whole percen
Natali5045456 [20]

Answer:

58.06%

Step-by-step explanation

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8 0
3 years ago
Heelp me im struggling
olga nikolaevna [1]

Answer:

b. -30

Step-by-step explanation:

the reason why it is B is because the operation in front of the number that stands alone without being a constant number that increases (or decreases) like the number 2, it has an x next to it which means that the number 2 is going to increase at a constant rate.

<em>hope it helps:)</em>

6 0
3 years ago
Please help logarithms!
nlexa [21]

Given:

\log_34\approx 1.262

\log_37\approx 1.771

To find:

The value of \log_3\left(\dfrac{4}{49}\right).

Solution:

We have,

\log_34\approx 1.262

\log_37\approx 1.771

Using properties of log, we get

\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_349      \left[\because \log_a\dfrac{m}{n}=\log_am-\log_an\right]

\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_37^2      

\log_3\left(\dfrac{4}{49}\right)=\log_34-2\log_37          [\log x^n=n\log x]

Substitute \log_34\approx 1.262 and \log_37\approx 1.771.

\log_3\left(\dfrac{4}{49}\right)=1.262-2(1.771)

\log_3\left(\dfrac{4}{49}\right)=1.262-3.542

\log_3\left(\dfrac{4}{49}\right)=-2.28

Therefore, the value of \log_3\left(\dfrac{4}{49}\right) is -2.28.

5 0
3 years ago
Help Answer Will Reward More Points!
schepotkina [342]

Answer:

use mathaway or math scanner they will help and provide you with the answer

6 0
3 years ago
rank has a circular garden. The area of the garden is 100 ft2. What is the approximate distance from the edge of Frank’s garden
Ray Of Light [21]

It is given that the area of the circular garden = 100 ft^2

Area of circle with radius 'r' = \pi r^2

We have to determine the approximate distance from the edge of Frank’s garden to the center of the garden, that means we have to determine the radius of the circular garden.

Since, area of circular garden = 100

\pi r^2 = 100

\frac{22}{7} \times r^2 = 100

r^2 = \frac{700}{22}

r^2 = 31.8

r = \sqrt{31.8}

So, r = 5.6 ft

r = 6 ft (approximately)

Therefore, the approximate distance from the edge of Frank’s garden to the center of the garden is 6 ft.

So, Option A is the correct answer.

7 0
3 years ago
Read 2 more answers
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