It has to be the 2 and 3 because when you multiply fractions you use keep change flip for example 2/3 divided by 2/3 you keep the first fraction 2/3 you change division to multiplication and you flip the last fraction which will be 2/3x3/2
Answer:
Step-by-step explanation:
A binary string with 2n+1 number of zeros, then you can get a binary string with 2n(+1)+1 = 2n+3 number of zeros either by adding 2 zeros or 2 1's at any of the available 2n+2 positions. Way of making each of these two choices are (2n+2)22. So, basically if b2n+12n+1 is the number of binary string with 2n+1 zeros then your
b2n+32n+3 = 2 (2n+2)22 b2n+12n+1
your second case is basically the fact that if you have string of length n ending with zero than you can the string of length n+1 ending with zero by:
1. Either placing a 1 in available n places (because you can't place it at the end)
2. or by placing a zero in available n+1 places.
0 ϵ P
x ϵ P → 1x ϵ P , x1 ϵ P
x' ϵ P,x'' ϵ P → xx'x''ϵ P
Answer:
See below
Step-by-step explanation:
22. 30 = 2 * 3 * 5
23. 126 = 2 * 3 * 3 * 7
24. 4900 = 2 * 2 * 5 * 5 * 7 * 7
25. 39204 = 2 * 2 * 3 * 3 * 3 * 3 * 11 * 11
26. There's no square number
27. The highest common factor are
30 is 5
126 is 7
4900 is 7
39204 is 11
28. The lowest common factor are
30 is 2
126 is 2
4900 is 2
39204 is 2
What about you? What did you get?
Answer:
1.-
2.-2x
Step-by-step explanation:
