Please help with these? thank you

Solve the fraction 1.2 1/2-1 1/4 2.1/2+1/4 3.1/3+2/5 4.1/2-1/3 5.1/4-1/3

DanielleElmas [232]

Answer:

Step-by-step explanation:

1. 1.25

2. 0.75

3.0.73333333333

4. 0.16666666666

5. 0.083333333333333

3 0

3 years ago

1) Solve the following equations : a)x/5 + 10 =15 b) 25x + 26 = 101

julia-pushkina [17]

Answer:

1a) 25, 1b) 3, 2a) 14, 2b) 4

Step-by-step explanation:

1a)

x/5 + 10 = 15

Subtract 10 from both sides:

x/5 = 15 - 10

x/5 = 5

Multiply both sides by 5:

x = 5 * 5

x = 25

1b)

25x + 26 = 101

Subtract 26 from both sides:

25x = 101 - 26

25x = 75

Divide both sides by 25:

x = 75/25

x = 3

2a)

Four less than a number is 10.

Let's call the number x. This means:

x - 4 = 10

Now add 4 to both sides:

x = 10 + 4

x = 14

2b)

The product of three and a number equals 12.

Let's call the number x. This means:

3 * x = 12

Now divide both sides by 3:

x = 12/3

x = 4

4 0

3 years ago

Lexiva is available in 350 mg tablets. How many mg will the patient take in 22 days

Anna11 [10]

Answer:

7700mg

Step-by-step explanation:

Since a tablet is 350mg

For 22days it going to take 350mg x 22 = 7700mg

7 0

3 years ago

If u(x) = x5 – x4 + x2 and v(x) = –x2, which expression is equivalent to (StartFraction u Over v EndFraction) (x)? x3 – x2 –x3 +

Len [333]

Answer:

^^look at the picture above it give you the answer^^

Step-by-step explanation

and the answer is C

your welcome hope it helps

7 0

3 years ago

Calculate the sample standard deviation and sample variance for the following frequency distribution of hourly wages for a sampl

lidiya [134]

Answer:

(a) The sample variance is 16.51

(a) The sample standard deviation is 4.06

Step-by-step explanation:

Given

$\begin{array}{cc}{Class} & {Frequency} & 8.26 - 10.00 & 20 &10.01-11.75 & 38 &11.76 - 13.50& 36 & 13.51-15.25 &25&15.26-17.00 &27 &\ \end{array}$

Solving (a); The sample variance.

First, calculate the class midpoints.

This is the mean of the intervals.

i.e.

$x_1 = \frac{8.26+10.00}{2} = \frac{18.26}{2} = 9.13$

$x_2 = \frac{10.01+11.75}{2} = \frac{21.76}{2} = 10.88$

$x_3 = \frac{11.76+13.50}{2} = \frac{25.26}{2} = 12.63$

$x_4 = \frac{13.51+15.25}{2} = \frac{28.76}{2} = 14.38$

$x_5 = \frac{15.26+17.00}{2} = \frac{32.26}{2} = 16.13$

So, the table becomes:

$\begin{array}{ccc}{Class} & {Frequency} & {x} & 8.26 - 10.00 & 20&9.13 &10.01-11.75 & 38 &10.88&11.76 - 13.50& 36 &12.63& 13.51-15.25 &25&14.38&15.26-17.00 &27 &16.13\ \end{array}$

Next, calculate the mean

$\bar x = \frac{\sum fx}{\sum f}$

$\bar x = \frac{20*9.13 + 38 * 10.88+36*12.63+25*14.38+27*16.13}{20+38+36+25+27}$

$\bar x = \frac{1845.73}{146}$

$\bar x = 12.64$

Next, the sample variance is:

$\sigma^2 = \frac{\sum f(x - \bar x)^2}{\sum f - 1}$

So, we have:

$\sigma^2 = \frac{20*(9.13-12.63)^2 + 38 * (10.88-12.63)^2 +...........+27 * (16.13 -12.63)^2}{20+38+36+25+27-1}$

$\sigma^2 = \frac{2393.6875}{145}$

$\sigma^2 = 16.51$

The sample standard deviation is:

$\sigma = \sqrt{\sigma^2}$

$\sigma = \sqrt{16.51}$

$\sigma = 4.06$

6 0

3 years ago