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garik1379 [7]
3 years ago
8

Jamal deposits $1000 into a savings account on his 18th birthday. If the 2% interest is compounded yearly, how much will he have

in the account on his 65th birthday?
Write your answer as a decimal rounded to the hundredths place. Do not include the dollar sign as part of your answer.
Mathematics
1 answer:
dalvyx [7]3 years ago
8 0
The number of years (n) that the deposit stayed in his balance is given by: 65 - 18 = 47 years.

The future value (FV) of a deposit (P), deposited at an interest rate of r% compounded yearly for n years is given by

FV=P(1+r)^n

Given that <span>Jamal deposits P = $1000 into a savings account on for n = 47years at 2% interest compounded yearly, the amount in his bank account at the end of the period is given by

FV=1000(1+0.02)^{47} \\  \\ =1000(1.02)^{47}=1000(2.53634) \\  \\ =\$2,536.34</span>
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What 15 divided by 100000= + 100 x 52 = + 998- 200 =
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We roll two fair 6-sided dice. Each of the 36 possible outcomes is assumed to be equally likely. (a) Given that the roll results
boyakko [2]

Answer:

a) \frac{1}{7}

b) \frac{2}{15}

Step-by-step explanation:

Given : We roll two fair 6-sided dice. Each of the 36 possible outcomes is assumed to be equally likely.

The outcomes are :

(1, 1) (1, 2)  (1, 3)  (1, 4)  (1, 5)  (1, 6)

(2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)

(3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6)

(4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)

(5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6)

(6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)

(a) Given that the roll results in a sum of 3 or more, find the conditional probability that doubles (the first and the second rolls result in the same number) are rolled.

Let P(A) be the probability of event that the roll results in a sum of 3 or more.

Except (1,1) rest sum is 3 or greater than 3.

So, P(A)=\frac{35}{36}

Now, P(A and B) is that the roll results in a sum of 3 or more and that doubles (the first and the second rolls result in the same number) are rolled.

i.e. (2,2), (3,3), (4,4), (5,5), (6,6) - 5

P(A\cap B)=\frac{5}{36}

The conditional probability is given by,

P(B|A)=\frac{P(A\cap B)}{P(A)}

P(B|A)=\frac{\frac{5}{36}}{\frac{35}{36}}

P(B|A)=\frac{5}{35}

P(B|A)=\frac{1}{7}

(b) Given that the two dice land on different numbers, find the conditional probability that the sum is 5.

Let P(A) be the probability of event that two dice land on different numbers.

Except (1,1),(2,2), (3,3), (4,4), (5,5), (6,6) rest two dice land on different numbers.

So, P(A)=\frac{30}{36}

Now, P(A and B) is that two dice land on different numbers and the sum is 5.

i.e. (1,4), (2,3), (3,2), (4,1) - 4

P(A\cap B)=\frac{4}{36}

The conditional probability is given by,

P(B|A)=\frac{P(A\cap B)}{P(A)}

P(B|A)=\frac{\frac{4}{36}}{\frac{30}{36}}

P(B|A)=\frac{4}{30}

P(B|A)=\frac{2}{15}

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blagie [28]

9514 1404 393

Answer:

  DNE

Step-by-step explanation:

An even-degree polynomial with a positive leading coefficient has no upper bound. The upper bound does not exist (DNE).

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