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garik1379 [7]
3 years ago
8

Jamal deposits $1000 into a savings account on his 18th birthday. If the 2% interest is compounded yearly, how much will he have

in the account on his 65th birthday?
Write your answer as a decimal rounded to the hundredths place. Do not include the dollar sign as part of your answer.
Mathematics
1 answer:
dalvyx [7]3 years ago
8 0
The number of years (n) that the deposit stayed in his balance is given by: 65 - 18 = 47 years.

The future value (FV) of a deposit (P), deposited at an interest rate of r% compounded yearly for n years is given by

FV=P(1+r)^n

Given that <span>Jamal deposits P = $1000 into a savings account on for n = 47years at 2% interest compounded yearly, the amount in his bank account at the end of the period is given by

FV=1000(1+0.02)^{47} \\  \\ =1000(1.02)^{47}=1000(2.53634) \\  \\ =\$2,536.34</span>
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Answer:

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Step-by-step explanation:

Tamira invests $5,000 in an account

Rate of interest = 4%

Time = 3 years

Case 1:

Principal = 5000

Rate of interest = 4%

Time = 3 years

No. of compounds per year = 1

Formula :A=P(1+r)^t

A=5000(1+0.04)^3

A=5624.32

There will be $5624.32 in the account after 3 years if the interest is compounded annually.

Case 2:

Principal = 5000

Rate of interest = 4%

Time = 3 years

No. of compounds per year = 2

Formula : A=P(1+\frac{r}{n})^{nt}

A=5000(1+\frac{0.04}{2})^{2 \times 3}

A=5630.812

There will be $5630.812 in the account after 3 years if the interest is compounded semi-annually.

Case 3:

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Rate of interest = 4%

Time = 3 years

No. of compounds per year = 4

Formula : A=P(1+\frac{r}{n})^{nt}

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A=5634.125

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Case 4:

Principal = 5000

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Time = 3 years

No. of compounds per year = 4

Formula :A=P(1+\frac{r}{n})^{nt}

A=5000(1+\frac{0.04}{12})^{12 \times 3}

A=5636.359

There will be $5636.359 in the account after 3 years if the interest is compounded monthly

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