Question

. Joanne does a daily walk from building P to building Q. Given point P(6,9) and point Q(5,-4), what is the distance between points P and Q on this campus map of the local college?

Answer 1

Answer:

The distance between points P and Q on this campus map of the local college is 13.038 units

Step-by-step explanation:

We are given that Joanne does a daily walk from building P to building Q

$P=(x_1,y_1)=(6,9)\\Q = (x_2,y_2)=(5,-4)$

We are supposed to find the distance between points P and Q on this campus map of the local college

We will use distance formula :

$d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute the values in the formula .

$d=\sqrt{(5-6)^2+(-4-9)^2}\\d=13.038$

Hence the distance between points P and Q on this campus map of the local college is 13.038 units