Answer: option D. 2x^2 + (3/2)x - 5
Explanation:
1) polynomials given:
f(x) = x/2 - 2 and g(x) = 2x^2 + x - 3
2) question: find (f + g) (x)
That means that f(x) + g(x), so you have to add up the two polynomials given.
3) x/2 - 2 + 2x^2 + x - 3
4) Combine like terms:
a) terms with x^2: you only have 2x^2, so it is not combined with other term.
b) terms with x: x/2 + x
that is a sum of fractions: x/2 + x = [x + 2x] / 2 = 3x / 2 = (3/2)x
c) constant terms: - 2 + (-3) = - 2 - 3 = - 5
5) Result: 2x^2 + (3/2)x - 5
That is the option d.
First, you must distribute 2(3x-1).
To do that, you will multiply 2•3x, and 2•-1 because you are taking the number outside of the parentheses and multiplying (distributing) it to all the numbers inside
After distributing, the left side of your inequality will be 6x-2
Now you have

To find the value of x, you must subtract an x value from both sides of the equation, as well as a constant from each side.
so you have

And that will make the equation

Now, divide the variable side, ***BUT, because you are dividing by a negative number in an inequality, the inequality will switch sides.
Then, the value of x is greater than or equal to 2
1. First consider the unknown original price as 'x'.
2. Then consider the rate of discount.
3. To find the actual discount, multiply the discount rate by the original amount 'x'.
4. To find the sale price, subtract the actual discount from the original amount 'x' and equate this to given sale price.