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3 years ago

How could I solve this equation, x+36=4x?

2 answers:

8 0

Try to put all the x-es on one side and then find a value of one x. In this case:

x + 36 = 4x / -x (both sides)
36 = 3x / :3 (both sides)
x = 12

horrorfan [7]3 years ago

5 0

Isolate 36 by subtracting x on both sides

36=4x-x
36=3x
divide both sides by 3
x=12

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A computer can be classified as either cutting dash edge or ancient. Suppose that 94% of computers are classified as ancient.

taurus [48]

Answer:

(a) 0.8836

(b) 0.6096

(c) 0.3904

Step-by-step explanation:

We are given that a computer can be classified as either cutting dash edge or ancient. Suppose that 94% of computers are classified as ancient.

(a) Two computers are chosen at random.

The above situation can be represented through Binomial distribution;

$P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 2 computers

r = number of success = both 2

p = probability of success which in our question is % of computers

that are classified as ancient, i.e; 0.94

LET X = Number of computers that are classified as ancient

So, it means X ~ $Binom(n=2, p=0.94)$

Now, Probability that both computers are ancient is given by = P(X = 2)

P(X = 2) = $\binom{2}{2}\times 0.94^{2} \times (1-0.94)^{2-2}$

= $1 \times 0.94^{2} \times 1$

= 0.8836

(b) Eight computers are chosen at random.

The above situation can be represented through Binomial distribution;

$P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 8 computers

r = number of success = all 8

p = probability of success which in our question is % of computers

that are classified as ancient, i.e; 0.94

LET X = Number of computers that are classified as ancient

So, it means X ~ $Binom(n=8, p=0.94)$

Now, Probability that all eight computers are ancient is given by = P(X = 8)

P(X = 8) = $\binom{8}{8}\times 0.94^{8} \times (1-0.94)^{8-8}$

= $1 \times 0.94^{8} \times 1$

= 0.6096

The above situation can be represented through Binomial distribution;

$P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 8 computers

r = number of success = at least one

p = probability of success which is now the % of computers

that are classified as cutting dash edge, i.e; p = (1 - 0.94) = 0.06

LET X = Number of computers classified as cutting dash edge

So, it means X ~ $Binom(n=8, p=0.06)$

Now, Probability that at least one of eight randomly selected computers is cutting dash edge is given by = P(X $\geq$ 1)

P(X $\geq$ 1) = 1 - P(X = 0)

= $1 - \binom{8}{0}\times 0.06^{0} \times (1-0.06)^{8-0}$

= $1 - [1 \times 1 \times 0.94^{8}]$

= 1 - $0.94^{8}$ = 0.3904

Here, the probability that at least one of eight randomly selected computers is cutting dash edge is 0.3904 or 39.04%.

For any event to be unusual it's probability is very less such that of less than 5%. Since here the probability is 39.04% which is way higher than 5%.

So, it is not unusual that at least one of eight randomly selected computers is cutting dash edge.

7 0

2 years ago

What is the solution to the liner equation That -12+3b-1=-5-b

andrew11 [14]

-13+3b = -5-b

4b -13 = -5
4b = 8

b= 2

4 0

3 years ago

Read 2 more answers

Fuel x costs $2 per gallon and fuel y costs $3 per gallon. You have at most $18 to spend on fuel. Write a system of linear inequ

madam [21]

Answer:

First choice A : 2x +3y is less than or equal to 18. x greater than or equal to 0. y greater than or equal to 0.

3 0

3 years ago

Read 2 more answers

Determine the value of sin○

Bezzdna [24]

Answer:

mera bahi mil nhi rha h abhay ko jante h

3 0

2 years ago

Read 2 more answers

Dave has $15 to

PSYCHO15rus [73]

Hello there! Given Dave only has $15 and the book is $8, we can assume he already paid for the book:

$15 - $8 = $7

Because Dave has $7 left, we can use the following inequality to show that he can spend up to $7 at maximum on both cards:

c = $7

Given Dave buys 2 cards, we can divide 7 by 2 to find how much Dave spends on each card:

7 divided by 2 gives us 3.50

Hence, Dave can spend $3.50 on each card.

Hope this helps!

6 0

1 year ago