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3 years ago

Vincent flipped three coins during a probability experiment. The outcomes of the first 40 trials are shown in the table.

Mathematics

2 answers:

Ilya [14]3 years ago

6 0

Answer:

Step-by-step explanation:

There are 40 trials, 16 out of those 40 trials resulted in two heads and one tail, which is what we are trying to find out of 120..

To do that, find 16/40 which gives you 0.4%

Next multiply 0.4% by 120 and you will get 48.

Hope this helped!

mr_godi [17]3 years ago

5 0

Answer:

Step-by-step explanation:

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Given that 3x – 4y= 22<br> -<br> Find & when y = -7

Liono4ka [1.6K]

<h2>Answer:</h2>

x=2

<h2><em><u>Step-by-step explanation:</u></em></h2>

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2 years ago

Y varies directly as x if y is 2 when x is 8 then the constant of variation is 1/4

sp2606 [1]

Answer:

a. True.

Step-by-step explanation:

y = kx

y = 2 when x = 8 gives:

2 = 8 * k

k = 2/8 = 1/4.

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2 years ago

find the centre and radius of the following Cycles 9 x square + 9 y square +27 x + 12 y + 19 equals 0

Citrus2011 [14]

Answer:

Radius: $r =\frac{\sqrt {21}}{6}$

$Center = (-\frac{3}{2}, -\frac{2}{3})$

Step-by-step explanation:

Given

$9x^2 + 9y^2 + 27x + 12y + 19 = 0$

Solving (a): The radius of the circle

First, we express the equation as:

$(x - h)^2 + (y - k)^2 = r^2$

Where

$r = radius$

$(h,k) =center$

So, we have:

$9x^2 + 9y^2 + 27x + 12y + 19 = 0$

Divide through by 9

$x^2 + y^2 + 3x + \frac{12}{9}y + \frac{19}{9} = 0$

Rewrite as:

$x^2 + 3x + y^2+ \frac{12}{9}y =- \frac{19}{9}$

Group the expression into 2

$[x^2 + 3x] + [y^2+ \frac{12}{9}y] =- \frac{19}{9}$

$[x^2 + 3x] + [y^2+ \frac{4}{3}y] =- \frac{19}{9}$

Next, we complete the square on each group.

For $[x^2 + 3x]$

1: Divide the $coefficient\ of\ x\ by\ 2$

2: Take the $square\ of\ the\ division$

3: Add this $square\ to\ both\ sides\ of\ the\ equation.$

So, we have:

$[x^2 + 3x] + [y^2+ \frac{4}{3}y] =- \frac{19}{9}$

$[x^2 + 3x + (\frac{3}{2})^2] + [y^2+ \frac{4}{3}y] =- \frac{19}{9}+ (\frac{3}{2})^2$

Factorize

$[x + \frac{3}{2}]^2+ [y^2+ \frac{4}{3}y] =- \frac{19}{9}+ (\frac{3}{2})^2$

Apply the same to y

$[x + \frac{3}{2}]^2+ [y^2+ \frac{4}{3}y +(\frac{4}{6})^2 ] =- \frac{19}{9}+ (\frac{3}{2})^2 +(\frac{4}{6})^2$

$[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =- \frac{19}{9}+ (\frac{3}{2})^2 +(\frac{4}{6})^2$

$[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =- \frac{19}{9}+ \frac{9}{4} +\frac{16}{36}$

Add the fractions

$[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =\frac{-19 * 4 + 9 * 9 + 16 * 1}{36}$

$[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =\frac{21}{36}$

$[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =\frac{7}{12}$

$[x + \frac{3}{2}]^2+ [y +\frac{2}{3}]^2 =\frac{7}{12}$

Recall that:

$(x - h)^2 + (y - k)^2 = r^2$

By comparison:

$r^2 =\frac{7}{12}$

Take square roots of both sides

$r =\sqrt{\frac{7}{12}}$

Split

$r =\frac{\sqrt 7}{\sqrt 12}$

Rationalize

$r =\frac{\sqrt 7*\sqrt 12}{\sqrt 12*\sqrt 12}$

$r =\frac{\sqrt {84}}{12}$

$r =\frac{\sqrt {4*21}}{12}$

$r =\frac{2\sqrt {21}}{12}$

$r =\frac{\sqrt {21}}{6}$

Solving (b): The center

Recall that:

$(x - h)^2 + (y - k)^2 = r^2$

Where

$r = radius$

$(h,k) =center$

From:

$[x + \frac{3}{2}]^2+ [y +\frac{2}{3}]^2 =\frac{7}{12}$

$-h = \frac{3}{2}$ and $-k = \frac{2}{3}$

Solve for h and k

$h = -\frac{3}{2}$ and $k = -\frac{2}{3}$

Hence, the center is:

$Center = (-\frac{3}{2}, -\frac{2}{3})$

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2 years ago

A shipment to a warehouse consists of 2,750 MP3 players. The manager chooses a random sample of 50

Juli2301 [7.4K]

MP3 players in the shipment which are likely to be defective is 330.

Step-by-step explanation:

• Probability is event of an occurrence which is uncertain.

• Probability always lies between 0 to 1.

• The sample of 50 MP3 has 6 defective, to solve it has to be converted.

• Convert percentage in 100 multiply numerator and denominator by 2.

• Result is 6/50 converted to 12/100, bring it to 0.12%.

• 12% is defected in 100% of sample.

• It is found here that 2750 is the population and 12% of 2750.

• 2750 * 0.12 = 330, defective pieces in 2750.

• There are three types of Classical,Empirical or Experimental.

• Classical are ‘n’ number of events find the probability occurrence.

• Empirical or experimental is purely based on events.

5 0

3 years ago

A line, line segment, or ray that intersects a line segment at its midpoint is a segment bisector. True or fals?

Leokris [45]

Answer:

true.

Step-by-step explanation:

hope this helps, i looked it up :)

7 0

2 years ago

Read 2 more answers