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3 years ago

Vincent flipped three coins during a probability experiment. The outcomes of the first 40 trials are shown in the table.

Mathematics

2 answers:

Ilya [14]3 years ago

6 0

Answer:

Step-by-step explanation:

There are 40 trials, 16 out of those 40 trials resulted in two heads and one tail, which is what we are trying to find out of 120..

To do that, find 16/40 which gives you 0.4%

Next multiply 0.4% by 120 and you will get 48.

Hope this helped!

mr_godi [17]3 years ago

5 0

Answer:

Step-by-step explanation:

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Dima020 [189]

Answer: A (1)

Explanation:

a(11) means column 1, row 1. Therefore, the answer would be the top left value.

8 0

3 years ago

X^3-10x=100

san4es73 [151]

Answer:

Step-by-step explanation:

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3 years ago

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Dmitrij [34]

Answer:

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3 years ago

Eric invited 200 of his friends to his graduation party. 75% of those invited said yes. 15% said no. The rest said maybe. 10% of

Ilia_Sergeevich [38]

Answer:

145

Step-by-step explanation:

75% of 200 = 150

75% + 15% = 90%

100% - 90% = 10%

10% of 200 = 20

10% of 150 = 15

150 + 15 - 20 = 145

145 friends attended the party.

4 0

3 years ago

Find the taylor series for f(x) centered at the given value of a. [assume that f has a power series expansion. do not show that

RUDIKE [14]

The taylor series for the f(x)=8/x centered at the given value of a=-4 is -2+2(x+4)/1!-24/16 $(x+4)^{2}$ /2!+...........

Given a function f(x)=9/x,a=-4.

We are required to find the taylor series for the function f(x)=8/x centered at the given value of a and a=-4.

The taylor series of a function f(x)= $f(a)+f^{1}(a)(x-a)/1!+ f^{11}(a)(x-a)^{2} /2! +f^{111}(a)(x-a)a^{3}/3!+..........$

Where the terms in f prime $f^{1}$ (a) represent the derivatives of x valued at a.

For the given function.f(x)=8/x and a=-4.

So,f(a)=f(-4)=8/(-4)=-2.

$f^{1}$ (a)= $f^{1}$ (-4)=-8/( $-4)^{2}$

=-8/16

=-1/2

The series of f(x) is as under:

f(x)=f(-4)+ $f^{1}(-4)(x+4)/1!+ f^{11}(-4)(x+4)^{2}/2!.............$

$=8/(-4)-8/(-4)^{2} (-4)(x+4)/1!+ 24/(-4)^{3} (-4)(x+4)^{2}/2!.............$

=-2+2(x+4)/1!-24/16 $(x+4)^{2}$ /2!+...........

Hence the taylor series for the f(x)=8/x centered at the given value of a=-4 is -2+2(x+4)/1!-24/16 $(x+4)^{2}$ /2!+...........

Learn more about taylor series at brainly.com/question/23334489

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3 0

1 year ago