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2 years ago

2x+y=4 -2x+y=-4 Answer for this equations and inequalities problem please

Mathematics

1 answer:

Elena-2011 [213]2 years ago

8 0

Answer:

(2,0); x = 2; y= 0

Step-by-step explanation:

add the system and u get y = 0. substitute in the first equation and u get x = 2

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-k/7=-4 i dont know how to do one step equations

AnnyKZ [126]

-k/7 = -4

k/7 = 4

k = 7 × 4

k = 28

5 0

2 years ago

Read 2 more answers

What is the true solution to the equation below?

Marina CMI [18]

Answer:

The solution is:

$x=4$

Step-by-step explanation:

Considering the expression

$lne^{lnx}+lne^{lnx}^{^2}=2ln8$

$\ln \left(e^{\ln \left(x\right)}\right)+\ln \left(e^{\ln \left(x\right)\cdot \:2}\right)=2\ln \left(8\right)$

$\mathrm{Apply\:log\:rule}:\quad \:log_a\left(a^b\right)=b$

$\ln \left(e^{\ln \left(x\right)}\right)=\ln \left(x\right),\:\space\ln \left(e^{\ln \left(x\right)2}\right)=\ln \left(x\right)2$

$\ln \left(x\right)+\ln \left(x\right)\cdot \:2=2\ln \left(8\right)$

$\mathrm{Add\:similar\:elements:}\:\ln \left(x\right)+2\ln \left(x\right)=3\ln \left(x\right)$

$3\ln \left(x\right)=2\ln \left(8\right)$

$\mathrm{Divide\:both\:sides\:by\:}3$

$\frac{3\ln \left(x\right)}{3}=\frac{2\ln \left(8\right)}{3}$

$\ln \left(x\right)=\frac{2\ln \left(8\right)}{3}.....A$

Solving the right side of the equation A.

$\frac{2\ln \left(8\right)}{3}$

$\ln \left(8\right):\quad 3\ln \left(2\right)$

Because

$\ln \left(8\right)$

$\mathrm{Rewrite\:}8\mathrm{\:in\:power-base\:form:}\quad 8=2^3$

⇒ $\ln \left(2^3\right)$

$\mathrm{Apply\:log\:rule}:\quad \log _a\left(x^b\right)=b\cdot \log _a\left(x\right)$

$\ln \left(2^3\right)=3\ln \left(2\right)$

$\frac{2\ln \left(8\right)}{3}=\frac{2\cdot \:3\ln \left(2\right)}{3}$

$\mathrm{Multiply\:the\:numbers:}\:2\cdot \:3=6$

$=\frac{6\ln \left(2\right)}{3}$

$\mathrm{Divide\:the\:numbers:}\:\frac{6}{3}=2$

$=2\ln \left(2\right)$

So, equation A becomes

$\ln \left(x\right)=2\ln \left(2\right)$

$\mathrm{Apply\:log\:rule}:\quad \:a\log _c\left(b\right)=\log _c\left(b^a\right)$

$=\ln \left(2^2\right)$

$=\ln \left(4\right)$

$\ln \left(x\right)=\ln \left(4\right)$

$\mathrm{Apply\:log\:rule:\:\:If}\:\log _b\left(f\left(x\right)\right)=\log _b\left(g\left(x\right)\right)\:\mathrm{then}\:f\left(x\right)=g\left(x\right)$

$x=4$

Therefore, the solution is

$x=4$

6 0

2 years ago

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136<5(-2-4b)-6

FinnZ [79.3K]

Answer:

−97

Answer:

−38

−22

n>7

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1 year ago

An arc is 6.5 cm long and it subtends a central angle of 45 degrees. Find the radius of the circle.

Orlov [11]

Arc length = radius * central angle (measured in radians)
There are 57.2957795131 degrees per radian so
45 degrees = (45 / 57.2957795131) = 0.7853981634 radians 
radius = arc length / central angle (radians)
radius = 6.5 / 0.7853981634 radians = 8.2760570408 cm

http://www.1728.org/radians.htm

8 0

2 years ago

Mrs. Purdue needs to pick three random students in her class to be representatives on the student council. Explain how Mrs. Purd

Xelga [282]

Answer:

See below

Step-by-step explanation:

She could have each student in the class write his or her name on a slip of paper and put it in a bowl. Then, she could shake the bowl and pull out any slip of paper with a student's name on it. After 3 times, the random sample would be over, and Mrs. Purdue would have her 3 representatives.

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2 years ago