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3 years ago

⭐️ help would be appreciated

Mathematics

1 answer:

serg [7]3 years ago

5 0

Hey there :)

f (x) = 5x² - 2x
g (x) = 3x² + x - 4

( f + g )( x ) is f ( x ) + g ( x )

5x² - 2x + 3x² + x - 4
Combine like-terms
5x² + 3x² - 2x + x - 4
8x² - x - 4

Your option will be the third option

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Science is Hayley's favorite class! She especially loves doing experiments. Today, she began

raketka [301]

Answer: the final mass of the solid is 176 grams.

Step-by-step explanation:

The "change" between two quantities, one initial Qi and one final Qf is defined as:

Change = Qf - Qi.

In this case, the quantity is mass, and we know that the initial mass is 260 grams.

And we also know that the change is -84 grams.

Then we have the equation:

Qf - 260 g = -84g

Qf = -84g + 260g = 176g

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8 0

3 years ago

Solve all of them please u get 30 points

nika2105 [10]

Step-by-step explanation:

from which text book please

8 0

2 years ago

Read 2 more answers

Unit 3 homework 6 Gina Wilson

Sonja [21]

Answer:

5) The equation of the straight line is 2 x - y + 1 =0

6) The equation of the straight line is x + y -5 =0

7) The equation of the straight line is 5 x + 6 y - 24 =0

8) The equation of the straight line is x - 4 y -4 =0

9) The equation of the parallel line is 3x + y -19 =0

Step-by-step explanation:

The equation of the straight line is

$y - y_{1} = m ( x - x_{1} )$

Slope of the line

$m = \frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

Given points are (1,3) , ( -3,-5)

$m = \frac{-5-3 }{-3-1 } = \frac{-8}{-4} = 2$

The equation of the straight line is

$y - y_{1} = m ( x - x_{1} )$

$y - 3 = 2 ( x - 1 )$

y = 2x - 2 +3

2 x - y + 1 =0

The equation of the straight line is 2 x - y + 1 =0

The equation of the straight line is

$y - y_{1} = m ( x - x_{1} )$

Slope of the line

$m = \frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

Given points are (1,4) , ( 6,-1)

$m = \frac{-1-(4) }{6-1 } = \frac{-5}{5} = -1$

The equation of the straight line is

$y - y_{1} = m ( x - x_{1} )$

$y - 1 = -1 ( x - 4 )$

y - 1 = - x +4

The equation of the straight line is x + y -5 =0

The equation of the straight line is

$y - y_{1} = m ( x - x_{1} )$

Slope of the line

$m = \frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

Given points are (-12 , 14) , ( 6,-1)

$m = \frac{-1-(14) }{6+12 } = \frac{-15}{18} = \frac{-5}{6}$

$y - 14 = \frac{-5}{6} ( x - (-12) )$

6( y - 14 ) = - 5 ( x +12 )

6 y - 84 = - 5x -60

5 x + 6 y -84 + 60 =0

5 x + 6 y - 24 =0

The equation of the straight line is

$y - y_{1} = m ( x - x_{1} )$

Slope of the line

$m = \frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

Given points are (-4 , -2) , ( 4 , 0)

$m = \frac{0+2}{4 +4} = \frac{2}{8} = \frac{1}{4}$

$y - (-2) =\frac{1}{4} ( x - (-4) )$

4 ( y + 2) = x + 4

x - 4 y -4 =0

The equation of the line y = 3x + 6 is parallel to the line

3x + y + k =0 is passes through the point ( 4,7 )

⇒ 3x + y + k =0

⇒ 12 + 7 + k =0

⇒ k = -19

The equation of the parallel line is 3x + y -19 =0

4 0

3 years ago

In how many ways can 10 people be seated in 10badjacenr seats in a theater

kupik [55]

3,628,800 is the correct answer

5 0

3 years ago

What is the image point of (4,−7) after a translation right 4 units and up 5 units?

Liono4ka [1.6K]

Answer:

(8, - 2 )

Step-by-step explanation:

A translation of 4 units right means add 4 to the x- coordinate

A translation of 5 units up means add 5 to the y- coordinate

(x, y ) → (x + 4, y + 5 ) ← translation rule, then

(4, - 7 ) → A'(4 + 4, - 7 + 5 ) → A'(8, - 2 )

5 0

3 years ago