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Masteriza [31]
3 years ago
15

Cound someone please help me on this, I'm stuck. ​

Mathematics
1 answer:
Katyanochek1 [597]3 years ago
5 0

Negative exponents work like this:

a^{-b}=\dfrac{1}{a^b}

So, in order to evaluate a negative exponent, you simply have to invert the base, and then raise to the positive equivalent of the exponent.

As an example, here are the first three exercises:

8^{-3}=\dfrac{1}{8^3}=\dfrac{1}{512}

(-4)^{-5}=\dfrac{1}{(-4)^5}=-\dfrac{1}{1024}

2k^{-4}=\dfrac{2}{k^4}

You can work out the rest applying this logic.

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The product of two numbers is the same as one of the factors. How can you use properties of multiplication to determine what the
Bess [88]
It will be as I understand:

(x*y)=x
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or (x*y)=y</span>
4 0
3 years ago
What is 784 divided 4
n200080 [17]
784/4 = 196

196 * 4 = 784

4 * 196 = 784

So the answer is : 196
8 0
3 years ago
Read 2 more answers
27.) Find the sum of the length of line segments EF and CD
Lelechka [254]

Answer:

5√10

Step-by-step explanation:

The distance between two points A(x_1,y_1) and B(x_2,y_2) on the coordinate plane is given by:

|AB|=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2 }

From the image attached the coordinates of the points are E(-1, -1), F(8, -4), C(-7, -4) and D(-1, 2).

Hence the lengths of the line segment EF and CD are:

|EF|=\sqrt{(8-(-1))^2+(-4-(-1))^2} =\sqrt{90}=3\sqrt{10} \\\\CD=\sqrt{(-1-(-7))^2+(-2-(-4))^2}=\sqrt{40}  =2\sqrt{10} \\\\Therefore:\\\\|EF|+|CD|=3\sqrt{10} +2\sqrt{10} =5\sqrt{10}

6 0
2 years ago
Multiply, (x+4)(x-4)  simplify answer.
trasher [3.6K]
That's the easily recognizable factored form of
the difference between two squares. Before
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x² - 16 .
3 0
3 years ago
Read 2 more answers
Hi guys can you help me factor these two equations?
mojhsa [17]
Problem # 1

Not Factored: (5x^2 - 13x - 6)
Factored: (5x + 2 )(x - 3)

There is no real "work" to be shown for this, you can see that
1) Seperating 5x^2 into 5x and x will get you the equation in the form:
 (5x     ) (x      )  = 5x^2 +

2) To complete this factor you need to guess which two numbers will add together to give you - 13x and multiply to form -6 (from the original unfactored equation). The numbers that will do this are 2 and 3

3) You can plug in negative or positives of those numbers to make sure they give you the exact results you need.

For example testing -2 and 3 you will get: (5x - 2) (x + 3 ) = 5(x^2) - 2x + 15x - 6 = 5x^2 +13x - 6.  This is NOT the same as the unfactored equation. So you know -2 and 3 is the wrong choice. Choosing 2 and -3 will give you the answer instead.

As i said, there's no actual "work" to show this, you have to make guesses and try to factor it.

-------------------------------------------------------------------------------------------------
Problem # 2

Not Factored: 4x^4 - 28x^3 + 48x^2
Factored: 4x^2 (x^2 - 7x + 12) =
                4x^2 (x  - 3) (x - 4)

To solve this, you factor out the 4x^2 from the entire equation. Then you can further factor the quadratic equation by seperating x^2 into (x    )(x    ) and guessing for which numbers will add to -7x and multiply to 12
6 0
3 years ago
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