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Masteriza [31]
3 years ago
15

Cound someone please help me on this, I'm stuck. ​

Mathematics
1 answer:
Katyanochek1 [597]3 years ago
5 0

Negative exponents work like this:

a^{-b}=\dfrac{1}{a^b}

So, in order to evaluate a negative exponent, you simply have to invert the base, and then raise to the positive equivalent of the exponent.

As an example, here are the first three exercises:

8^{-3}=\dfrac{1}{8^3}=\dfrac{1}{512}

(-4)^{-5}=\dfrac{1}{(-4)^5}=-\dfrac{1}{1024}

2k^{-4}=\dfrac{2}{k^4}

You can work out the rest applying this logic.

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19 - (- 41)<br> plzzzzzz help fast!
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Answer:

60

Step-by-step explanation:

Is because when you have two negative -- signs it became positive

19 + 41 = 60

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makkiz [27]
The answer is 3x^2 +3x
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3 years ago
Hello, I really struggle with math and I was wondering if you could help me with the following problem please? It will be much a
xz_007 [3.2K]

Answer:

x=7

Step-by-step explanation:

Simplifying

3x + 2(4 + 6x) = 113

3x + (4 * 2 + 6x * 2) = 113

3x + (8 + 12x) = 113

Reorder the terms:

8 + 3x + 12x = 113

Combine like terms: 3x + 12x = 15x

8 + 15x = 113

Solving

8 + 15x = 113

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-8' to each side of the equation.

8 + -8 + 15x = 113 + -8

Combine like terms: 8 + -8 = 0

0 + 15x = 113 + -8

15x = 113 + -8

Combine like terms: 113 + -8 = 105

15x = 105

Divide each side by '15'.

x = 7

Simplifying

x = 7

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